Timeline for How can I find polygons in convex hull?
Current License: CC BY-SA 4.0
15 events
when toggle format | what | by | license | comment | |
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Jan 31, 2021 at 18:00 | history | tweeted | twitter.com/StackMma/status/1355938904373944323 | ||
Jan 29, 2021 at 21:13 | answer | added | kglr | timeline score: 4 | |
Jan 29, 2021 at 19:51 | answer | added | Michael E2 | timeline score: 3 | |
Jan 29, 2021 at 19:17 | comment | added | alessandro | @Peter Hilgers I don't think the second image necessarily indicates that Mathematica's internal representation treats those polygons as separate. It could be that that with that plot theme it just doesn't render the edges of the (triangular) polygons. | |
Jan 29, 2021 at 19:06 | answer | added | Daniel Huber | timeline score: 2 | |
Jan 29, 2021 at 14:38 | history | edited | MarcoB | CC BY-SA 4.0 |
Formatted code
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Jan 29, 2021 at 14:03 | comment | added | Peter Hilgers | @kglr: This looks good, probably, I will study in detail, thanks for the hint. | |
Jan 29, 2021 at 14:00 | comment | added | kglr | does this answer work for you? | |
Jan 29, 2021 at 13:59 | comment | added | kglr | related/possible duplicate: Construct a polyhedron from the coordinates of its vertices and calculate the area of each face | |
Jan 29, 2021 at 13:59 | comment | added | Peter Hilgers | @Ulrich Neumann: That is a possibility, but the second image shows that Mathematica has the answer internally. Is the no way to extract it? | |
Jan 29, 2021 at 13:54 | comment | added | Ulrich Neumann | Perhaps: Try to combine neighboring triangles with the same normal? | |
Jan 29, 2021 at 13:34 | comment | added | Peter Hilgers | I use Mathematica 12 | |
Jan 29, 2021 at 13:28 | comment | added | J. M.'s missing motivation♦ | What version of Mathematica are you using? | |
Jan 29, 2021 at 13:25 | review | First posts | |||
Jan 29, 2021 at 14:04 | |||||
Jan 29, 2021 at 13:20 | history | asked | Peter Hilgers | CC BY-SA 4.0 |