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Timeline for Quick Wolfram Question

Current License: CC BY-SA 4.0

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Dec 24, 2019 at 6:38 comment added WReach +1, also: Sum[x /. Solve[x^i == x + 1 && x > 0][[1]], {i, 2, 9}] // N
Dec 24, 2019 at 2:43 comment added Philip Yeranosian I ran the program by the way. It computes all the numbers positive numbers x s.t. x^n = x+1. Numbers like 1.618, 1.3247, 1.2207, etc. Its a sequence approaching 1 in the limit. Then I added all the decimal parts: .618 + .3247 + .2207 etc and found that it was divergent. Then I took the first 1000 sums and compared it to the first 10000 sums and I found a constant ratio of 1.596. Is there a concept for this? The ratio of divergent sums computed at logarithmic intervals.
Dec 23, 2019 at 21:40 review Low quality posts
Dec 23, 2019 at 22:45
Dec 23, 2019 at 21:23 history answered Ulrich Neumann CC BY-SA 4.0