Timeline for Find $\frac{dy}{dx}$ if $x\sqrt{1+y}+y\sqrt{1+x}=0$
Current License: CC BY-SA 3.0
7 events
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Apr 19, 2018 at 13:19 | comment | added | Max Coplan | @yarchik That's better now. OP did ask for the answer to be y'=-1/(x+1)^2, which is a function of x. UlrichNeumann now has it in terms of x | |
Apr 19, 2018 at 6:51 | history | edited | Ulrich Neumann | CC BY-SA 3.0 |
added 313 characters in body
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Apr 18, 2018 at 22:09 | comment | added | Sooraj Soman | thnx. but i am trying to get the same simplified answer as i have obtained whn solved myself. | |
Apr 18, 2018 at 21:11 | comment | added | yarchik | @MaxCoplan Why not, the OP has not said that the answer should be in terms of x. | |
Apr 18, 2018 at 20:47 | review | Low quality posts | |||
Apr 18, 2018 at 22:03 | |||||
Apr 18, 2018 at 20:45 | comment | added | Max Coplan | How does that answer the OP's question? | |
Apr 18, 2018 at 20:17 | history | answered | Ulrich Neumann | CC BY-SA 3.0 |