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Timeline for ListVectorPlot contour lines

Current License: CC BY-SA 3.0

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Jul 1, 2016 at 14:18 vote accept alessandro
Jul 1, 2016 at 13:50 answer added Jason B. timeline score: 1
Jul 1, 2016 at 13:13 comment added alessandro @Feyre: sorry I needed to suffer a bit before discovering that, in ListVectorDensityPlot[], without ColorFunctionScaling -> False, nothing was shown but an uniform background... yes, it's a first step although I preferred lines
Jul 1, 2016 at 13:11 comment added alessandro @JasonB: vx or vy, they're both good
Jul 1, 2016 at 13:09 comment added Jason B. What do you want the contours to be based on, vx, vy, the vector magnitude Norm[{vx, vy}]^2?
Jul 1, 2016 at 13:02 comment added alessandro (the vector field I'm using is at s000.tinyupload.com/… as a matlab export datafile, if somebody wants to play with it)
Jul 1, 2016 at 13:01 comment added alessandro @JasonB: I thought it was a great idea using StreamPoints, until I realized that the streamlines are exactly perpendicular to the direction I need, that is the contour line!
Jul 1, 2016 at 13:00 comment added alessandro @J.M.: I never used it so probably I made some mistake. I tried this syntax: ListVectorPlot[tt, VectorPoints -> 40, Mesh -> 20, MeshFunctions -> {#1 &}] and though I get no error, I see no meshes...
Jul 1, 2016 at 12:46 comment added Jason B. Two options come to mind, first the StreamPoints option VectorPlot and ListVectorPlot. Second, you could just use Show to combine different types of 2D plots
Jul 1, 2016 at 12:09 comment added J. M.'s missing motivation Have a look at MeshFunctions.
Jul 1, 2016 at 11:46 comment added Feyre As in ListVectorDensityPlot[]? It doesn't have lines, but really lines just clutter up such a graph. You might have to superimpose two graphs if you really want the lines themselves.
Jul 1, 2016 at 11:44 history asked alessandro CC BY-SA 3.0