Timeline for ContourPlot does not find contours that RegionPlot finds
Current License: CC BY-SA 3.0
17 events
| when toggle format | what | by | license | comment | |
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| Mar 24, 2016 at 21:08 | history | tweeted | twitter.com/StackMma/status/713110190208450560 | ||
| Mar 24, 2016 at 17:37 | answer | added | Edmund | timeline score: 1 | |
| Mar 24, 2016 at 16:58 | vote | accept | Rho Phi | ||
| Mar 24, 2016 at 16:52 | answer | added | user484 | timeline score: 6 | |
| Mar 24, 2016 at 16:43 | history | edited | Rho Phi | CC BY-SA 3.0 |
added a function that has this issue
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| Mar 24, 2016 at 16:42 | comment | added | Rho Phi | @Rahul that's true! quite weird to me. Any reason why this should be different? | |
| Mar 24, 2016 at 16:32 | comment | added | user484 |
Interestingly, ContourPlot[0.000157223 10^(2 x - 2 y) == 100, {x, -6, -1}, {y, -6, -1}] does plot the contour.
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| Mar 24, 2016 at 16:28 | comment | added | Rho Phi |
You can use this one 0.000157223 10^(2 x -2 y) and compare RegionPlot[ 0.000157223 10^(2 x - 2 y) > 100, {x, -6, -1}, {y, -6, -1}] and ContourPlot[0.000157223 10^(2 x - 2 y), {x, -6, -1}, {y, -6, -1}, Contours -> { 100}, ContourShading -> False]
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| Mar 24, 2016 at 16:28 | answer | added | george2079 | timeline score: 5 | |
| Mar 24, 2016 at 16:15 | comment | added | MarcoB | Roberto, as you can see, we are shooting blind here. We need to have access to the function, or even better, to a minimal working example that exhibits the same problem, to provide meaningful help. | |
| Mar 24, 2016 at 16:14 | history | edited | MarcoB | CC BY-SA 3.0 |
Formatted code
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| Mar 24, 2016 at 16:09 | comment | added | Jason B. |
@RobertoFranceschini - you could execute CopyToClipboard[f[x,y]] and then go to gist.github.com and paste it there. That way we can work with the function without having to really look at it
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| Mar 24, 2016 at 16:09 | comment | added | Rho Phi |
@george2079 Thanks, I tried that, and MaxRecursion but they are of no help here. It only helps if I do the plot in a smaller range in which the contours end up being. In the original range the contours would be only in the lower right part of the frame.
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| Mar 24, 2016 at 16:07 | comment | added | Rho Phi | @JasonB The specific f I have today is something you do not want to look at :) it comes from a long manipulation of inputs. | |
| Mar 24, 2016 at 16:02 | comment | added | george2079 |
try PlotPoints
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| Mar 24, 2016 at 16:01 | comment | added | Jason B. |
So, um, can I see what f looks like? :-)
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| Mar 24, 2016 at 15:58 | history | asked | Rho Phi | CC BY-SA 3.0 |