Timeline for Using Functions as Arguments to Function
Current License: CC BY-SA 3.0
7 events
| when toggle format | what | by | license | comment | |
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| Sep 19, 2012 at 2:49 | comment | added | diracdeltafunk | Yes but as I said above I need to have MyNorm'[{x,y,z}] evaluate to Dt[myNorm[{x, y, z}], t] | |
| Sep 19, 2012 at 2:28 | comment | added | Mark McClure |
belisarius' answer strikes me as correct. If $x$, $y$, and $z$ are, in fact, functions (even in symbolic, as in x[t]), then this works fine. If they are not, then their derivatives should be zero.
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| Sep 19, 2012 at 2:18 | comment | added | Dr. belisarius | @Ben7005 Edit your question and add all the relevant info | |
| Sep 19, 2012 at 2:09 | comment | added | diracdeltafunk |
In addition, I need to have MyNorm'[{x,y,z}] evaluate to Dt[myNorm[{x, y, z}], t].
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| Sep 19, 2012 at 2:05 | comment | added | diracdeltafunk | While this does give the derivative of the norm function, when I attempt deriving myNorm[r[t]] where r[t] is a piecewise parametric function in three parts {x[t], y[t], z[t]}, it still returns an error message. | |
| Sep 19, 2012 at 2:03 | review | Low quality posts | |||
| Sep 19, 2012 at 2:33 | |||||
| Sep 19, 2012 at 1:59 | history | answered | Dr. belisarius | CC BY-SA 3.0 |