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Member for 9 years, 10 months
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Last seen more than 3 years ago
At his request, this is how I would edit @belisarius's answers (using 9.0.1): l = {"http://i.stack.imgur.com/t95sV.jpg", "http://i.stack.imgur.com/MVP47.jpg", "http://i.stack.imgur.com/...
It seems quad-tree decomposition would suit your needs: http://demonstrations.wolfram.com/QuadTreeImageDecomposition/
With only one argument, ImageAdjust[img] performs histogram stretching, ie. pixel values, which run from min to max in img, are rescaled so they run from 0 to 1 in the ouput image. The setting {...
Edit: ImageTransformation and ImagePerspectiveTransformation accept Image3D objects and corresponding transformations as of Mathematica 10. Waiting for ImageTransformation to accept Image3D objects, ...
Some, yes. For example, many image processing functions are multi-threaded. One way to see whether a function is leveraging multi-threading is to perform the same kind of tests as for ImageResize in ...
Since texture synthesis using Inpaint has already been mentioned, let me add for the record the obvious, easy, dirty, but sometimes satisfying technique of mirroring: i = ImageTake[ExampleData[{"...
This is about 100 times faster than g3kk0's answer on my machine---the results are identical: imageStack = Image[ColorCombine@Import["ExampleData/CTengine.tiff", "ImageList"], "Real"]; ImageApply[...
It is already the case that the "convolution component of EdgeDetect is multithreaded." EdgeDetect is composed of a sequence of operations. Some of these operations are indeed multi-threaded, and ...
This function first converts to "RGB", then inquires about the presence of an alpha channel. If there is none, it adds one. Then it returns the data cast as type "Byte" by default. Casting to 8-bit ...
In your sequence, the first image has 2 corners that are too close to the boundary and ImageFeatureTrack has troubles tracking those. If you rerun your experiments with added padding, things work ...
It is arbitrary to assign a color space to data that do not have one attached to them. What about using "XYZ" if one is looking for a linear color space? i = Import@"http://www.4p8.com/eric.brasseur/...
The function q3[#] & is not Listable and because the Interleaving option value is True by default, there is not much optimization that can be figured out automatically. Setting the Listable ...
In EdgeDetect[image, radius, threshold], the radius is expressed in pixels, and the threshold corresponds to normalized pixel values (ie. in the range from 0 to 1). @Silvia, there may be differences ...
To search only for lines at given angles, say between theta0 and theta1, you could: Compute the Hough transform using Radon[img, dims, {theta0, theta1}, Method -> "Hough"] Detect peaks in the ...
Everybody seems happy already at the time of this answer. But the following resources will help a newcomer develop good habits: Volume Rendering And Processing Image3D (esp. the section Details and ...
(Would have applied an "honorable" tag to the question if possible) It is fair to use ImageAdjust[image, {contrast, brightness}] both for your "control" image and "data" image, because with these ...
We could do with ground truth data to assess the result. Is this acceptable as a first step? Manipulate[ HighlightImage[ i, result = Binarize[TopHatTransform[i, radius], thr]], ...
Don't use ImageTake if your coordinates are (x;y) image coordinates and not (row;col) positions. ImageTrim[image, {{x,y}}, 10] works as expected. You may want to check out the section "Coordinate ...
There is not a built-in function that can tell where two images have the same pixels, but it's not hard to build one: imageSame[image1_, image2_] := Image[ImageApply[Boole@TrueQ[#1 == #2] &, ...
This functionality is not available in ImageLines in the sense that you can only select from the detected segments a posteriori, not guide the detection by restricting the range of allowed segments. ...
As an alternative to ImageTake, ImagePad will do the job using the syntax ImagePad[img, {{left, right}, {bottom, top}}]: img = Import["ExampleData/rose.gif"]; In[10]:= ImagePad[img, {{0, -10}, {0, 0}}...