5 votes
Accepted

Reduce a MeijerG to elementary function

It looks like Mathematica is not trying any of the known transformations of the Meijer G-functions. We can use the second formula on this Wolfram Functions page, ...
  • 41.3k
4 votes
Accepted

Series expansion using binomial theorem in Mathematica

$Version (* "13.2.1 for Mac OS X ARM (64-bit) (January 27, 2023)" *) Clear["Global`*"] f[x_] := (1 - a/x)^(1/3) Do a series expansion about <...
  • 140k
4 votes

Series expansion using binomial theorem in Mathematica

You are almost there. Try the following: Series[(1 - (a/x))^(1/3), {a, 0, 2}] // Normal (* 1 - a^2/(9 x^2) - a/(3 x) *) Have fun!
3 votes

Subtituting kronecker deltas for products in simplification

You can use ReplaceAll. Also, avoid capitalizing your symbols. ...
  • 12k
3 votes

How to express the argument through the function?

No chance for mix of exponentials and powers: Solve[a==f[d,B],d] This one is working at least with implicit roots ...
  • 121
3 votes

Getting the terms containing rational exponents to zero in an expression

Rational numbers are atomic (i.e., cannot be divided into subexpressions) AtomQ[3/4] (* True *) Consequently, rationals have ...
  • 140k
3 votes
Accepted

Getting the terms containing rational exponents to zero in an expression

PossibleIntegerQ[a_, n] := Resolve[Exists[n, Element[n, Integers], Element[a, Integers]]] expr /. f[x]^a_. /; ! PossibleIntegerQ[a, n] -> 0 (* f[x] *) ...
  • 41.3k
2 votes

How to preserve the order of expressions in the asymptotic expansion?

First you might simplify your code using NestList ...
2 votes
Accepted

How to preserve the order of expressions in the asymptotic expansion?

I can only answer the title of your question regarding the preservation of order, for which there are already several questions on this site. Working upon the answer from @march, you can use the ...
  • 12k
2 votes
Accepted

Simplify complex conjugation and force joining of exponentials

You used SuperStar, which has no inherent meaning in Mathematica and stays unevaluated. Use Conjugate instead. ...
  • 12k
2 votes

How to print particular cases with Integrate?

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  • 140k
2 votes

FullSimplify returns unevaluated

...
  • 140k
1 vote

Subtituting kronecker deltas for products in simplification

A variation of @Domen's answer is as follows: ...
1 vote
Accepted

How to get Mathematica to give me a specific alternate form?

I am not sure if this answers your question, but you can use a combination of ComplexExpand, Factor and ...
  • 972
1 vote

FullSimplify returns unevaluated

Only workaround: ...
1 vote

FullSimplify returns unevaluated

The help file for Abs says: gives the absolute value of the real or complex number z. In your case, x isn't explicitly a real or complex number so Abs[x] returns unevaluated. You may be able to ...
  • 67.1k
1 vote

How to print particular cases with Integrate?

yes but this integral exists even if u+v= +/- 1 Then do the following ...
  • 127k

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