5
votes
Accepted
Reduce a MeijerG to elementary function
It looks like Mathematica is not trying any of the known transformations of the Meijer G-functions.
We can use the second formula on this Wolfram Functions page,
...
- 41.3k
4
votes
Accepted
Series expansion using binomial theorem in Mathematica
$Version
(* "13.2.1 for Mac OS X ARM (64-bit) (January 27, 2023)" *)
Clear["Global`*"]
f[x_] := (1 - a/x)^(1/3)
Do a series expansion about <...
- 140k
4
votes
Series expansion using binomial theorem in Mathematica
You are almost there. Try the following:
Series[(1 - (a/x))^(1/3), {a, 0, 2}] // Normal
(* 1 - a^2/(9 x^2) - a/(3 x) *)
Have fun!
- 37k
3
votes
Subtituting kronecker deltas for products in simplification
You can use ReplaceAll. Also, avoid capitalizing your symbols.
...
- 12k
3
votes
How to express the argument through the function?
No chance for mix of exponentials and powers:
Solve[a==f[d,B],d]
This one is working at least with implicit roots
...
- 121
3
votes
Getting the terms containing rational exponents to zero in an expression
Rational numbers are atomic (i.e., cannot be divided into subexpressions)
AtomQ[3/4]
(* True *)
Consequently, rationals have ...
- 140k
3
votes
Accepted
Getting the terms containing rational exponents to zero in an expression
PossibleIntegerQ[a_, n] :=
Resolve[Exists[n, Element[n, Integers], Element[a, Integers]]]
expr /. f[x]^a_. /; ! PossibleIntegerQ[a, n] -> 0
(* f[x] *)
...
- 41.3k
2
votes
How to preserve the order of expressions in the asymptotic expansion?
First you might simplify your code using NestList
...
- 43k
2
votes
Accepted
How to preserve the order of expressions in the asymptotic expansion?
I can only answer the title of your question regarding the preservation of order, for which there are already several questions on this site. Working upon the answer from @march, you can use the ...
- 12k
2
votes
Accepted
Simplify complex conjugation and force joining of exponentials
You used SuperStar, which has no inherent meaning in Mathematica and stays unevaluated. Use Conjugate instead.
...
- 12k
2
votes
2
votes
1
vote
Subtituting kronecker deltas for products in simplification
A variation of @Domen's answer is as follows:
...
- 7,989
1
vote
Accepted
How to get Mathematica to give me a specific alternate form?
I am not sure if this answers your question, but you can use a combination of
ComplexExpand, Factor and ...
- 972
1
vote
1
vote
FullSimplify returns unevaluated
The help file for Abs says: gives the absolute value of the real or complex number z. In your case, x isn't explicitly a real or complex number so Abs[x] returns unevaluated. You may be able to ...
- 67.1k
1
vote
How to print particular cases with Integrate?
yes but this integral exists even if u+v= +/- 1
Then do the following
...
- 127k
Only top scored, non community-wiki answers of a minimum length are eligible