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1 vote
Accepted

Obtaining different answers when using NDSolve vs ParametricNDSolveValue

Solutions computed with NDSolve and ParametricNDSolve are the same as it follows from the test ...
  • 37.6k
5 votes
Accepted

ListInterpolation and extrapolation: order has been reduced,

ListInterpolation does not expect a list of $\{x_i, y_i\}$ values. The way you are using it, Mathematica interprets it as a 2D array, and in one dimension you have ...
  • 33.3k
4 votes

ListInterpolation and extrapolation: order has been reduced,

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  • 135k
0 votes

Solve a parametric equation in 2 variables

Let us do the following: Step 1: ...
0 votes

Solve a parametric equation in 2 variables

Regarding only real variables and parameters. Due to Cos multiple solutions represented by C1,C2 ...
  • 17k
6 votes

2D cross-section of ParametricPlot3D

Also using MeshFunctions. Using MeshShading -> {Automatic, None} or ...
  • 49.5k
7 votes

2D cross-section of ParametricPlot3D

We may set the z component to a given value and then solve for e.g.u. Then we have u[v]. This then defines a line. The problem here is, that the solution is multivalued. We therefore create as many ...
  • 35.5k
8 votes

2D cross-section of ParametricPlot3D

Clear["Global`*"] {fx, fy, fz} = { (29/25)^v Cos[v] (1 + Cos[u]), -(29/25)^v Sin[v] (1 + Cos[u]), -2 (29/25)^v (1 + Sin[u])}; The values of <...
  • 135k
8 votes

2D cross-section of ParametricPlot3D

With z constant, the third term in your parametrized vector is equal to said constant and defines a relationship between the parameters u and v. ...
  • 2,523
11 votes

2D cross-section of ParametricPlot3D

We can use the MeshFunctions options and extract the slice data accordingly. ...
  • 34.1k

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