New answers tagged labeling
6
Update: As an alternative and more flexible approach, we can post-process ContourPlot output to inject contour labels.
ClearAll[addLabels]
addLabels[colors_, labels_: Automatic, threshold_: 1/3][g_Graphics] :=
Module[{diag = ArcLength@Line[Transpose @ PlotRange @ g],
assoc = AssociationThread[colors,
labels /. Automatic ->
MapIndexed[...
1
names = CountryData[];
data = CountryData[#, {"Population", {1920, 2010}}] & /@ names;
cleaned = DeleteMissing[data /. {} -> Nothing];
sum = TimeSeriesThread[Total, cleaned];
DateListLogPlot[sum,
FrameLabel -> {{"one", "two"}, {"three", "four"}},
LabelStyle -> Directive[Red, Bold, 16],
...
0
The syntax in use in that other question is:
{#, ScientificForm@#} & /@ Range[min_value, max_value, increment]
where min_value is the lower bound of the axis, max_value is the upper bound, and increment is the spacing between successive labeled tick marks. In your case, a setting of min_value of -40000, max_value of 0, and increment of 10000 gives ...
3
Update
Added ResourceFunction SymmetricSort to Wolfram Function Repository.
With m, order, and neworder from below then
ResourceFunction["SymmetricSort"][m, order, neworder]
OP
When you reorder the correlation matrix you must preserve the diagonal and the relationship between the variables.
For correlation matrix m
m = Transpose@MapIndexed[
{v,...
3
Try this. To be precise, let us assume that the following
matr={{7, 10, -2, 3, -4}, {-8, -8, -9, 3, 3}, {5, -1, 7, 9, -5}, {4, -9, 0, -7, -10}, {10, 5, -9, 8, -9}};
is your matrix to be rearranged.
Here are your lists of old and new headings:
lst = {a, b, c, d, e};
lst2 = {c, a, e, b, d};
Let us determine positions of the elements of lst2 in the lst:
...
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