2
$Version
(* "12.2.0 for Mac OS X x86 (64-bit) (December 12, 2020)" *)
Clear["Global`"]
There is no need to use Table with RandomVariate to generate multiple values.
SeedRandom[1234];
data = RandomVariate[NormalDistribution[], 10^5];
SmoothHistogram[data, Automatic, "PDF", Frame -> True, PlotRange -> All,
FrameLabel -...
2
Try this:
SmoothHistogram3D[data,
Ticks -> {
{#, DateString[#, {"Day", "/", "Month", "/", "YearShort", " ", "Hour24Short", ":", "MinuteShort"}]} & /@
FindDivisions[MinMax@data[[All, 1]], 5],
Automatic,
Automatic}
]
Look at the documentation of ...
Only top voted, non community-wiki answers of a minimum length are eligible
