# Tag Info

Accepted

### Extract boundary points of an interpolating function obtained by NDSolve

We can use "Domain" to extract the values. {rmin, rmax} = (h /. sol[])["Domain"][]; rmin rmax
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### Plotting an integral with solving for a specific constant

As an example, we take a simple function that we can integrate analytically: f[t_] = t + 2; Integrate analytically: ...
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### Strange behavior of GroebnerBasis

Obviously MMA consider n as a variable. You can see this by writing: GroebnerBasis[1/(n (n - 1)) + x, {x, n}] what is the same as your result. To circumvent this, ...

### How to modify the order of symbols to make the result more logical

The warning by @Bill in a comment about *Form functions is well made. The following works, but it appears that PolymonialForm ...
1 vote

### Solution of a sixth degree polynomial

It is advantageous to solve the expression for x first and introduce new parameters a -> \[Alpha] M, r -> \[Rho] M: ...

### How to modify the order of symbols to make the result more logical

The function "rearrange" The function rearrange[expr,listOfFinalPositions] rewrites a sum in the order prescribed by the list entitled "...

### FindRoot with input as a list

Your equations are simple enough that you can use Solve: Solve[{eq1==0, eq2==0, eq3==0}, {a, b, d}] {{a -> -60, b -> (k (...
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...
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### Solution of a sixth degree polynomial

Evaluating M and a, this can be done as follows. ...

### How can I choose the integer numbers a, b, c, d, t so that the equation $\sqrt{a x^2+b x+c}=d x+t$ has two integer solutions?

No need to use FindInstance. In fact you can generate all possible equations with prescribed roots r1 and ...

### Adding Points on an Elliptic Curve

You can code this as follows (for distinct p1,p2): ...
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### Getting all solutions to an equation on condition the variables are either 0 or 1

FWIW this can be solved by brute force: e.g. b = Tuples[{0, 1}, 3]; t = Tuples[{0, 1}, 8]; sol[s_] := Select[t, Mod[# . b, 2] == s &] Solutions can be ...

### Getting all solutions to an equation on condition the variables are either 0 or 1

An equivalent version to user64494's answer is the following: ...

### Getting all solutions to an equation on condition the variables are either 0 or 1

This can be done as follows. ...
1 vote

### Multiple solutions from NSolve

With the OP's sol, we can gather the similar solutions together, find their mean, and if desired, polish them up with FindRoot: <...
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### How to solve this integral equation numerically?

Although the general problem in the question probably requires the methods referenced by flinty in 285076, the specific problem contained in the question's code, ...
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### Numerical solving diffusion equation in spherical coordinates

Change your boundary conditions to DirichletConditions ...
1 vote

### First order differential equation with two conditions

To long for a comment! You might check your expected solutions directly. Examplary for the first one ...
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### Problems with Solve. Only works for specific parameters. Solve function do not "start"

Your claim "the programm [program] do [does] not start the Solve function process" is not true: the returned inputs mean the Solve cannot solve those and ...

### Solving A System of Two Implicit Equations

An alternative approach is to use FindRoot or FindMinimum without constructing an ...
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### Selecting Solve results according to conditions

You can add those conditions in Solve, but you also need to specify eg that $a>0$: ...

### Selecting Solve results according to conditions

There could be shorter way. How about f[x_, y_] := L x y; g[x_, y_] := x^2 + y^2 - a; res = SolveValues[D[f[x, y] + λ g[x, y], {{x, y, λ}}] == 0, {x, y}, λ] and ...
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### Solving A System of Two Implicit Equations

First plot the function you want tointerpolate ...

1 vote

### How to solve this integro-differential equation in Mathematica?

Mathematica can't solve your integral equation, DSolve only returns a simplified form I think: ...

### Solve[] isn't producing a correct result

To long for a comment NSolve evaluates all zeros for given parameter parameters (from @Larson's GeoGebra picture ) ...
1 vote

### Is there a way to divide associations by key?

a = <|A -> 2.02015, B -> 1.98025|>; b = <|B -> 0.538000, A -> 0.462000|>; In the above case it's simply ...