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Questions using the Sum command, especially for series and other algebraic objects, and related functions such as SumConvergence

8
votes
The sum is a little strange, because the multinomial coefficient makes sense only when $k_1+k_2+\ldots+k_n=m$. I will assume this restriction is (implicitly) intended and that $n$ is fixed. (If not, …
answered Feb 14 '13 by whuber
12
votes
The Simplify idea is on the right track, but you have to tell Mathematica about the relationship between f and Plus in a slightly different way: ClearAll[f]; Plus[f[x_], f[y_]] /; x + y == 1 ^:= 1 …
answered Dec 20 '12 by whuber
2
votes
The formula is a little vague because starting limits for the $n_i$ are not given. However, its form suggests it started out as $$\sum_{(n_1, n_2, \ldots, n_k) \mid 1 \le n_i \wedge n_1+n_2+\cdots+n …
answered Jan 24 '13 by whuber