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Questions on creating visualizations from functions or data using high-level constructors such as Plot, ListPlot, Histogram, etc.

1
vote
RevolutionPlot3D accepts only a maximum of two variables for iteration in the form RevolutionPlot3D[f, {t, ...}, {θ, ...}]. Nevertheless, one can manipulate the third: Manipulate[RevolutionPlot3D[r^ …
answered Dec 6 '13 by István Zachar
5
votes
I don't think this can be done with Mesh, as this would require non-continuous mesh lines along the horizontal dimension, which (according to my knowledge) is not possible in ArrayPlot. But you can ea …
answered Oct 14 '13 by István Zachar
8
votes
You can specify InterpolationOrder -> 0 in ListPlot, and you can specify different orders for different datasets: ListPlot[{montecarlo, MapIndexed[{First@#2 + .5, #1} &, data]}, PlotMarkers -> {Sp …
answered Apr 11 '13 by István Zachar
6
votes
Use ImagePadding -> {{left, right}, {bottom, top}}: BarChart[data, PlotRange -> {{0, 25}, {0, 100}}, ChartLabels -> {Placed[l, Axis], Placed[{"", ""}, Bottom]}, PlotLabel -> label, AxesLabel -> { …
answered Apr 11 '13 by István Zachar
3
votes
Mathematica by default cannot always guess what humans find aesthetic. In your case, it assumes the standard aspect ratio of 1/GoldenRatio. Specifying a ratio of 1 though is not enough, as the plot ra …
answered Jun 7 '13 by István Zachar
2
votes
In version 9 one can use the builtin PlotLegends option, but pre-9 it seems like the "PlotLegends`" package messes up coordinate display. In this case, fall back to create your own legend. For that, d …
answered Mar 23 '13 by István Zachar
2
votes
For function plotting: f[x_] := x^2; (* define a function to plot *) df = 1/4; (* define a step size for the arrows *) g[x_] := Sin[x]; dg = Pi/16; { Plot[f[x], {x, -5, 5}, Epilog -> Table[{Red …
answered Dec 6 '13 by István Zachar
1
vote
Use Solve. f1[m1_] := Sqrt[2] Sqrt[Sqrt[1/m1^2 + 20 Sqrt[3118] (1/m1)^(3/2) Sqrt[1/50] + 3118020 Sqrt[3118] Sqrt[1/m1] (1/50)^(3/2) + 24304810001/50^2 + 623602/(m1*50)] - 10 S …
answered Jan 23 '14 by István Zachar
4
votes
You could specify seed-points for streamlines directly using StreamPoints: only those stremlines will be plotted which pass through these points. Here I set up two point sets: one at $y = 1$ and anoth …
answered Mar 27 '13 by István Zachar
8
votes
Use the inequality to sow all integer coordinates that are inside the boundary of the region when iterating through all integer pairs of the full range: pts = First@Last@Reap@Do[If[x >= 4 y && x <= 4 …
answered Dec 11 '12 by István Zachar
6
votes
This is just a crude approximation of what you expect using Inset, but it becomes rather complicated to track subplot coordinates when Insetted in a larger Graphics environment. My method requires th …
answered Dec 18 '12 by István Zachar
6
votes
While Eli's answer is elegantly simple, it has a drawback: the Prolog objects are layered on top of GridLines, thus a background rectangle covers all the gridlines. So to come over this issue, here is …
answered Apr 17 '12 by István Zachar
13
votes
Why not use the mouse cursor? This version shows the zooming frame when CTRL is pressed. f[x_] := Sin[x] + 0.05 Cos[10 x]; DynamicModule[{p}, Dynamic@MouseAppearance[ Plot[f[x], {x, 0, Pi}], …
answered Nov 29 '15 by István Zachar
12
votes
1answer
When I set the Antialiasing option in Style, I get the followings: plot = ListContourPlot[ Table[Sin[i + j^2], {i, 0, 2, 0.05}, {j, 1.2, 2, 0.05}], ColorFunction -> ColorData["AvocadoColors"], …
asked Jan 20 '12 by István Zachar
5
votes
You got very close to the solution: you simply have to pair up the positions and the year values, and feed it to the bottom FrameTicks specification (as in FrameTicks->{{left, right}, {bottom, top}}). …
answered Jun 28 '12 by István Zachar

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