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Questions on the manipulation of matrices in Mathematica.

4
votes
The worst ones are order 10^-15. This is effectively zero, so the negative values are only a result of mathematica working with finite numerical precision.
answered Nov 24 '16 by Wouter
0
votes
As @Rahul pointed out in the comments, it is impossible to start from the unit matrix and change J such that the eigenvectors change continuously. However, I found a nice way to keep track of the …
answered Dec 28 '15 by Wouter
2
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1answer
$ yields a diagonal matrix. Now, I'm not really satisfied with the default ordering. For constructing the matrices, I first define, with eg. $L=5,n=1;$ the vectors dmcos = Array[- Cos[-Pi + 2 Pi (# - 1 … )/L ] &, L]; dn = ConstantArray[J, L - n]; If the matrix is already diagonal (M0=DiagonalMatrix[dmcos]) the expected and orthogonal matrix of eigenvectors would be the identity-matrix of course …
asked Dec 23 '15 by Wouter