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Frequently Asked Question – a tag for original questions which have a multitude of duplicates

39
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I want to solve the trigonometric equation : $$(3-\cos 4x )\cdot (\sin x - \cos x ) = 2.$$ I tried Solve[(3 - Cos[4*x])*(Sin[x] - Cos[x]) == 2, x] It returns the solutions in terms of Root objects …
asked Oct 28 '12 by minthao_2011
7
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First, I put $t = \sin x - \cos x$, eq1 = (3 - Cos[4x]) ( Sin[x] - Cos[x]) - 2 == 0; eq2 = t == Sin[x] - Cos[x]; Eliminate[ TrigExpand[ {eq1, eq2}], x] I receive 2 t - 2 t^3 + t^5 == 1 And then, …
answered Oct 28 '12 by minthao_2011