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Questions on applying common nonlinear scalings to functions or data--useful for making sense of data which varies over a large range.

3 votes
Accepted

Cannot Plot Log

$Version (* "11.1.1 for Mac OS X x86 (64-bit) (April 18, 2017)" *) Use Rationalize Clear[f] f[n_, prec_: 25] := Module[{rn = Rationalize[n, 0]}, N[1 - x^(2^(rn + 1)^a - 2^rn^a) /. {a -> 1 …
Bob Hanlon's user avatar
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0 votes

Scaling a LogPlot to better show its minimum

Amplifying on m_goldberg's answer Clear[fun3, h] Since Cos[1.] (* 0.540302 *) use of Abs is unnecessary. Or just use Set rather than SetDelayed in defining fun3 fun3[h_] = (2*epsilon*Abs[Cos[1 …
Bob Hanlon's user avatar
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1 vote

Nothing showing up on my LogLogPlots

a[f_] := 25000/(1 + (I*f)/200) ReImPlot[a[f], {f, 0.1, 10000}, PlotRange -> All, ScalingFunctions -> {"Log", None}, PlotLegends -> Placed[Automatic, {.35, .6}]] LogLogPlot[Abs[a[f]], {f, 0.1, 100 …
Bob Hanlon's user avatar
  • 163k
1 vote

Problem with automatic numbering of values for logarithmic plotting, e.g., 0.00 substituted ...

THIS IS NOT AN ANSWER BUT RATHER AN EXTENDED COMMENT The linked notebook in the OP does not handle precision as you expect. For example, a = N[Rationalize[0.3493100380781557152479242154255860286824835 …
Bob Hanlon's user avatar
  • 163k
2 votes

Floating LogScale histogram

With v13.1 it is necessary to omit specifying the PlotRange $Version (* "13.1.0 for Mac OS X x86 (64-bit) (June 16, 2022)" *) Clear["Global`*"] SeedRandom[1234]; Histogram[ RandomVariate[NormalDi …
Bob Hanlon's user avatar
  • 163k
3 votes

Plot with ScalingFunctions->{"Infinite",interval}

$Version (* "13.3.1 for Mac OS X ARM (64-bit) (July 24, 2023)" *) Clear["Global`*"] lam[pi2_] := 1/(2 pi2 - 1); gama[pi2_, a_, t_] := 1 - Exp[lam[pi2]*t] + 2 lam[pi2]^2*t*(pi2 - a)*Exp[lam[pi2]* …
Bob Hanlon's user avatar
  • 163k
6 votes
Accepted

Issue with combining weighted data log histograms

Even the uneweighted data can have display (offset) problems when using Show. Also the data3 histogram obscures portions of the stacked histogram. SeedRandom[500]; data1 = RandomVariate[NormalDistri …
Bob Hanlon's user avatar
  • 163k
6 votes

LogPlot axes labels destroyed when working in high precision

EDIT: Problem persists with Mathematica version "10.3.1 for Mac OS X x86 (64-bit) (December 9, 2015)" THIS IS NOT AN ANSWER but rather an extended comment providing an update for Mma v10.1. In looki …
Bob Hanlon's user avatar
  • 163k
1 vote

Contour plot of the imaginary portion of a function given the real part is positive

You can use Piecewise and set its default to an imaginary number so that nothing is plotted for default values. ContourPlot[ Piecewise[{{ Im[x + I*y - Log[x + I*y]], Re[x + I*y - Log[x + I*y …
Bob Hanlon's user avatar
  • 163k
1 vote
Accepted

Control of SurvivalFunction probability scale

$Version (* "11.3.0 for Mac OS X x86 (64-bit) (March 7, 2018)" *) With your xmax == 1000, I get an error message of General::munfl (i.e., machine underflow) which is a new error message in version …
Bob Hanlon's user avatar
  • 163k
4 votes
Accepted

How can I make a NumberLineLogPlot'?

Use the option Ticks intervals = {{1 <= x <= 10}, {10 <= x <= 100}, {100 <= x <= 1000}}; logIntervals = intervals /. {n_?NumericQ :> Log10[n]} (* {{0 <= x <= 1}, {1 <= x <= 2}, {2 <= x <= 3}} *) N …
Bob Hanlon's user avatar
  • 163k
3 votes
Accepted

Partially log x-axis?

You can use an Inset to zoom in to the Plot. Using Plot in the Inset is easier to read than using LogLinearPlot Clear["Global`*"]; Manipulate[ Plot[ 1/Abs[x - 5/1000]*1/Abs[x - 7/1000]* Exp[19* …
Bob Hanlon's user avatar
  • 163k
1 vote
Accepted

How can I annotate a ListLogLinearPlot with Graphics and Text?

I think this is probably compatible with v9 $Version (* "14.0.0 for Mac OS X ARM (64-bit) (December 13, 2023)" *) Clear["Global`*"] cosData = Table[{N[x], N[Cos[x]]}, {x, 0, 13 Pi, Pi/20}]; point …
Bob Hanlon's user avatar
  • 163k
3 votes
Accepted

How to plot this data with errorBar

data = {{{13.952, 364.7}, ErrorBar[36.4]}, {{19.13, 309.11}, ErrorBar[30.9]}, {{21, 294.159}, ErrorBar[29.4]}, {{26.2635, 237.26}, ErrorBar[23.7]}, {{29.0713, 191.367}, ErrorBar[19 …
Bob Hanlon's user avatar
  • 163k
1 vote

The different solution compare to the book solution?

Clear["Global`*"] expr = Sqrt[(3 x)/(x + 2 d)] d/(x - d); G[d_, x_] = Integrate[expr, x] (* -(1/(Sqrt[3] Sqrt[x])) 2 d Sqrt[x/(2 d + x)] Sqrt[ 2 d + x] (Sqrt[3] ArcTanh[(d - x + Sqrt[x] Sqrt[2 d …
Bob Hanlon's user avatar
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