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Results tagged with string-manipulation
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user 731
Questions on the manipulation of String objects in Mathematica, and the functions used for these manipulations.
2
votes
StringCases functionality on a varying rows of data
One way using string patterns and StringCases like this:
string = ImportString["<12> cfg <15.21> bhg v<(24)> e<65> True
<12> cfg <15.21> bhg v<33> e<(77)> False
<83> fff <67> …
- 71.2k
4
votes
Accepted
StringCases functionality
You say you manipulated the string before and that's why it's missing a brace at the end. It looks like you may have deformed a JSON string, in which case you did yourself a big disservice as such lis …
- 71.2k
2
votes
Swap first and last names in a list
Two ways I think will work for you, if not please provide some sample data:
list = ImportString["Lastname, Firstname, Initial
Lastname, Firstname, Initial
Lastname, Firstname, Initial
Lastna …
- 71.2k
20
votes
Accepted
Opposite of StringSplit
A combination of StringJoin and Riffle:
res = StringSplit["a b c d e f g"," "];
StringJoin@Riffle[res," "]
- 71.2k
17
votes
Accepted
Get all pairs of same consecutive characters from string?
str = "AabHHioPjggtYuggbwq";
StringCases[str, x_ ~~ x_, IgnoreCase -> True]
{"Aa", "HH", "gg", "gg"}
Or in the generalized version of the question:
str = "AaAbHHhhhioPjggtYuggGgGbwq";
StringCa …
- 71.2k
3
votes
Accepted
How to add the capital letters to Caesar´s Code?
I think you can work this out on your own so I wasn't intending to answer it, but I'll answer it since I'm not satisfied with the other answers so far. This is the simplest extension, in my mind, to y …
- 71.2k
7
votes
Accepted
Rule-based deletions from string list
You would need something like DeleteSubsequenceCases, but it doesn't exist. I would recommend this instead:
SequenceReplace[lis, {d_?(StringMatchQ[NumberString]), ___, "X"} :> d]
If X only appears …
- 71.2k
7
votes
Extract substrings with defined length from a string
Using Repeated:
StringCases[
str,
Repeated[_, {3}] ~~ " and " ~~ Repeated[_, {3}],
Overlaps -> True
]
{"his and tha", "hit and tha"}
Note the use of Overlaps which is necessary for strings such …
- 71.2k
7
votes
How to capitalize the first letter of each word in a string
While I endorse Mr.Wizard's pattern matching solution and I've given Istvàn +1 I would also like to submit this function which is meant to not rely on string patterns and be as readable as possible:
…
- 71.2k
1
vote
How to construct tuples with a given order?
It's a brute force approach:
set = CharacterRange["A", "E"];
n = 4;
tuples = Tuples[set, n];
Select[tuples, Order[#[[1]], #[[2]]] == 1 && And @@ Negative@Differences@Ordering@Rest[#] &]
{"A", " …
- 71.2k
1
vote
How to remove duplicate characters from a string?
Just another way to do it without converting the string to a list. You have to define the character range.
rest[x_ /; x == {}] := {}
rest[x_] := Rest[x]
str = "113233454766";
(str = StringReplacePa …
- 71.2k
2
votes
Accepted
Mathematica regex equvalent of \l
I believe this is what you want.
StringCases["Abba", RegularExpression["(.).*(?=(?i:\\1))[a-z]"]]
(?=(?i:\\1)) is a lookahead which says, "if the next character matches \1 in any case," but then it …
- 71.2k
3
votes
Splitting strings at lower case characters and numbers
elements = SortBy[ElementData[#, "Abbreviation"] & /@ ElementData[], Minus@*StringLength];
StringCases["Fe3O2", DigitCharacter .. | elements]
{"Fe", "3", "O", "2"}
(Thanks to Mr.Wizard for synt …
- 71.2k
2
votes
How do I pad numbers to the left so that all are the same length?
One way:
If[StringLength@# == 1, "0" <> #, #] &@*ToString /@ {-6, 1, 3, 23}
Another way:
StringJoin@*(ToString /@ PadLeft[#, 2] &)@*Characters@*ToString /@ {-6, 1, 3, 23}
- 71.2k
6
votes
A too complicated lookup
Another option:
AssociationThread[nm -> ln]["tat"]
If you store AssociationThread[lm -> ln] in a symbol you can use it for many quick lookups without having to recreate the association every time.
…
- 71.2k