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Results tagged with procedural-programming
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user 731
Questions about Mathematica's procedural programming paradigm.
10
votes
How do I achieve the function of Continue using Catch and Throw?
If you wrap the body of the loop with Catch, then any Throw will act as Continue:
r = 0;
Do[Catch[
If[EvenQ[i], Throw[Null]];
r += i
], {i, 10}];
r
(* Out: 25 *)
(Example taken from the do …
- 71.2k
4
votes
Accepted
Changing iteration variable in Do loop
This is one the cases where For can be helpful (generally it's just more complicated.) With For, you can manipulate the iteration variable, which you cannot do with Do.
Example:
For[
i = 1,
i <= 4 …
- 71.2k
3
votes
Accepted
How to use syntax instead of double for loop
If I understand it correctly, you're looking to compute the distance matrix of those two sets of vectors. This can be done, as Jason says, using Outer. It can also be done using the built-in function …
- 71.2k
1
vote
Skip time taking loop values to take input next value after certain time
Here is an example of MarcoB's suggestion:
AbsoluteTiming[
TimeConstrained[Print[Pause[1]; 1], 3];
TimeConstrained[Print[Pause[5]; 10], 3];
TimeConstrained[Print[Pause[2]; 100], 3];
]
You can thi …
- 71.2k
3
votes
Better to use loop or function when populated list?
Like this:
computeEffect[xEffect_] := With[{offset = RandomInteger[{1, 10}]},
If[xEffect - offset < 1,
RandomValue,
randomA[[xEffect - offset]] + k randomB[[xEffect - offset]]
]
]
effec …
- 71.2k
9
votes
Accepted
Replace elements of a list based on a function
To answer your question directly, a loop could be written like this:
f = Table[3*k*k, {k, 1, 16}];
Do[
f[[4 i + j]] = 1;
,
{i, {1, 3}},
{j, 1, 4}
];
f
{3, 12, 27, 48, 1, 1, 1, 1, 243, 300, …
- 71.2k