Search Results
| Search type | Search syntax |
|---|---|
| Tags | [tag] |
| Exact | "words here" |
| Author |
user:1234 user:me (yours) |
| Score |
score:3 (3+) score:0 (none) |
| Answers |
answers:3 (3+) answers:0 (none) isaccepted:yes hasaccepted:no inquestion:1234 |
| Views | views:250 |
| Code | code:"if (foo != bar)" |
| Sections |
title:apples body:"apples oranges" |
| URL | url:"*.example.com" |
| Saves | in:saves |
| Status |
closed:yes duplicate:no migrated:no wiki:no |
| Types |
is:question is:answer |
| Exclude |
-[tag] -apples |
| For more details on advanced search visit our help page | |
Results tagged with units
Search options not deleted
user 704
Questions about using, converting, or interpreting units of measurement in Mathematica.
8
votes
1
answer
470
views
Moles/Liters doesn't get simplified to Molar even though Molar*Liters gets simplified to Moles
Why can't Mathematica 9 simplify mol/L to M, when it can simplify M*L to mol?
Quantity["Moles" / "Liters"] // UnitSimplify
(* => 1 mol/L *)
Quantity["Molar" * "Liters"] // UnitSimplify
(* => 1 m …
CommunityBot
- 1
-2
votes
1
answer
237
views
Make Quantity behave reasonable with Degrees Celsius
When using a Quantity with the unit of "DegreesCelsius" multiplication doesn't work as expected.
If you have 10 degrees and multiply it by 2 you get 20 degrees instead of the expected 293,15 degrees.
…
- 108k
6
votes
Simpler input for the new unit support
Improved version of Simon's answer which tries several different transformation of the input string to convert it to the full form that Mathematica needs:
Begin["System`"]
(* Deca is intentionally l …
- 1,565
1
vote
1
answer
128
views
Extract function parameters from "unevaluated" FormBox
I want to get the abbreviation for a Unit from its full name eg. "Newtons" => "N".
Using TraditionalForm on Quantity will show the abbreviation and doing the following will show the code returned by …
CommunityBot
- 1
2
votes
0
answers
157
views
Insert a Quantity Unit literal in TraditionalForm
Is there a keyboard shortcut for creating something like the result of this:
Quantity["Kilograms" * ("Meters")^2 / ("Seconds")^2]
After copying the result to a TraditionalForm field it looks like t …
- 5,636