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Results tagged with equation-solving
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user 472
Questions on the analytic and numerical equation solving functions of Mathematica (Solve, Reduce, NSolve, FindRoot, DSolve, RSolve, etc.).
0
votes
0
answers
68
views
Solve a simple equation for a unknown indexed by a real number
I have the following equation.
f[a,b,Q]=1 - Q*Exp[b] + Exp[a]*(Exp[b]^3 - Exp[b]^4 + 2*Exp[b]^5 -
2*Q*Exp[b]^5 - Q*Exp[b]^6 + Q^2*Exp[b]^7) + Exp[a]^2*(-Exp[b]^9 + Exp[b]^(10))
and I want to solve …
- 455
2
votes
0
answers
112
views
Consistent ordering of Root results from Solve
For higher order bivariate polynomials, if I want to find the roots I'll expect answer using Root[], e.g. from the help pages,
In[1]:= Solve[x^5 + 2 x + 1 == 0, x]
Out[1]= {
{x -> Root[1 + 2 #1 + # …
- 455
2
votes
0
answers
486
views
Invert a transcendental function
I have tried Reduce and Solve in Mathematica, as well as have a long list of tries in Maple, but cannot seem to get anywhere solving the following for V:
V^P * (V-1)^Q == c^(P-Q) * X^Q * (V-c^2)^Q,
…
- 455
2
votes
1
answer
148
views
Another using Solve output for further calculations
I probably missed a question already posted as this topic seems common, but I looked at several, e.g. Using result of Solve in further calculations
and am a little stuck. I didn't understand the use o …
- 455
2
votes
Accepted
Another using Solve output for further calculations
Much more in the spirit of the question, J.M. had a better answer:
In[1]:= sol =
y /. {ToRules[
Reduce[x^2 - 3 y^2 + 3 == 0, y, Complexes,
Backsubstitution -> True]]}
Out[1]= {-(Sqrt[3 + …
- 455