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Results tagged with string-manipulation
Search options answers only
not deleted
user 1997
Questions on the manipulation of String objects in Mathematica, and the functions used for these manipulations.
3
votes
How do I extract a number from a string?
Consider:
str = "thiru37aa2er45"
then
StringCases[str, DigitCharacter ..]
yields:
{"37", "2", "45"}
StringCases[str, DigitCharacter .]
yields:
{"3", "7", "2", "4", "5"}
They can be conve …
- 64.8k
18
votes
How can I generate a list of combinations of string joins?
You can also use Tuples:
a = {"a", "b", "c"};
n = {"1", "2", "3"};
StringJoin @@@ Tuples[{a, n}]
- 64.8k
3
votes
How to join two strings one of which is Subscript?
In Mathematica version 10, StringTemplate can allow you to convert to string, e.g.
st = StringTemplate[
"Pythagoras theorem: \!\(\*SuperscriptBox[\(`1`\), \
\(2\)]\)+\!\(\*SuperscriptBox[\(`2`\), …
- 64.8k
2
votes
How do I complete this function len for the length of a line segment?
If your aim is to measure multiple line segments you can apply your function or in-built functions to list. You can also use RegionMeasure (1 dimension) or ArcLength for Line.
Consider the polygon:
…
- 64.8k
1
vote
Options in a StringReplace rule
Perhaps not what you are after:
op[] := Function[x,
x /. MapThread[
Rule[#1, (#2)] &, {{"t", "t1", "t2"},
Thread["t" -> {"0", "T1", "1"}]}]];
srf[opts_: "t"] := StringReplace["content …
- 64.8k
4
votes
How to switch between a binary number as String and a as a list of digits?
Just some other functions to consider:
IntegerDigits an take a base argument, e.g. IntegerDigits[5,2] yields {1,0,1}
FromDigits is the inverse: FromDigits[{1,0,1},2] yields 5
If the issue is for di …
- 64.8k
8
votes
Accepted
How could I transform the YYYYDDD date string/Integer to YYYYMMDD date string?
Perhaps, using:
dateslalala={2003364, 2003157, 2003314, 2003302, 2003181, 2003062, 2003254, \
2003070, 2003365, 2003338, 2003233, 2003073, 2003020, 2003010, \
2003238, 2003107, 2003310, 2003347, 2003 …
- 64.8k
1
vote
Replacing every nth comma in string output with "\n"
I am somewhat confused about the aim. Here is an interpretation. Starting with string:
string = "{{13,{17,4},{23,10},220/13,3},{17,{23,6},{29,12},4368/17,3},\
{19,{23,6},{29,12},4368/19,3},{23,{29,6} …
- 64.8k
2
votes
Adding numbers to a list
Note you could just do:
Sort["x" <> ToString[#] & /@ Range[12]]
If you have list you can also use MapIndexed:
xs = ConstantArray["x", 12];
Sort@MapIndexed[#1 <> ToString[#2[[1]]] &, xs]
- 64.8k
2
votes
Applying different values to string row
Perhaps:
t = {1, 4, 4, 22, 3, 12, 54, 65};
a = ">}{<"
Row[{"{<"}~Join~Riffle[t, a]~Join~{">}"}]
or
l = "{<";
r = ">}";
Row[{l, ##, r} & @@ Riffle[t, Row[{r, l}]]]
- 64.8k
7
votes
Characters to numbers
v = ToExpression /@ StringSplit["000101", ""]
yields:
{0,0,0,1,0,1}
ToExpression["000101"]
yields:
101
- 64.8k
2
votes
Element combinations
SplitBy[lis,NumericQ] /. {{x__String} :> StringJoin[x], {x_?NumericQ} :> x}
- 64.8k
4
votes
Sorting alphanumeric strings
Narrow but FWIW:
strings[[Ordering[(Characters /@
strings) /. {{x_, y_} :> {x, 0, y}}]]]
- 64.8k
2
votes
Accepted
Importing data to make a DateListPlot
I make the assumption that your imported data is of the form {{20131217, 123123.}, {20140313, 321321.},...}. If the date is a string then omit the String function in the following. You need to convert …
- 64.8k
5
votes
Graph showing valid English words obtained by insertion of single characters
I post this (if I understand the question from title and text: single letter addition anywhere in string) to illustrate how unwieldy the graph gets just 3 levels deep. Here just starting with "a".
fu …
- 64.8k