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Questions about the use of built-in Mathematica functions, including pure functions.

2 votes

How to use ForAll in Reduce

Perhaps you mean something like this: f[{x1_, x2_}, {y1_, y2_}] := x1 y2 - x2 y1 Reduce[ForAll[{x1, x2, y1, y2}, {x1, x2}.{y1, y2} <= f[{x1, x2}, {y1, y2}]]]
murray's user avatar
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2 votes

How to define and use a linear function

For the record... no function, whether defined by SetDelayed (:=) or Set (=) expliclty or by constructing a pure function (using # and &) is needed. To wit: -800 {3, 7} + 12000 {9600,6400}
murray's user avatar
  • 12.1k
2 votes
0 answers
130 views

Which functions automatically generate new functions?

output from dict = Nearest[WordData[]] is a NearestFunction object -- a function that may then be evaluated at an input such as: dict["eleephannt"] {elephant} How can one determine which other functions
murray's user avatar
  • 12.1k
1 vote

How to get the correct answer when solve this equation?

I don't think this is substantially different from what @Daniel Lichtblau proposed, but it directly uses your code up to the final Solve expression, where it also uses the trick of squaring in order t …
murray's user avatar
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2 votes

Efficient way to test if all the elements in a list are Integers?

Use Map, abbreviated /@. For example: lis = {4, 5/2, 3., 6/3, Pi}; IntegerQ /@ lis (* or Map[IntegerQ, lis] *) (* {True, False, False, True, False} *)
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7 votes
1 answer
203 views

What kind of creature is h[c] for definition h[c_][x_] := (* function of x and c *)

To implement "Hero's Method" for approximating $\sqrt{c}$, one iterates the function (x + c/x)/2 for a given number c (e.g., 2) starting with some initial value of x. This can be implemented by defini …
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  • 12.1k
3 votes
Accepted

Trouble creating a bifurcation diagram of a trajectory

As noted, you didn't show a Mathematica definition of f. Moreover, the definitions of traj is incorrect, and the syntax of Manipulate is wrong. Here's a corrected, complete version: f[x_, a_] := a - …
murray's user avatar
  • 12.1k
4 votes
Accepted

How to use external Mathematica Code?

Note that there is another, newer, way to store definitions that may suit your purposes: to store then as local objects (or even as cloud objects), then retrieve them when needed. I'll illustrate with …
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1 vote

Detecting errors and providing alternative results

You have a fundamental error in your use of MatrixForm: as things stand, the value of distanc is not a (nested) list to which you can Apply another function; rather, distanc is just a special output f …
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4 votes
1 answer
464 views

How hide symbolic definition of a function?

How can the actual definition of a function be hidden from a user? I want the user of a notebook to be able to evaluate a real-valued function f of a real variable at any particular numeric input yet …
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  • 12.1k
29 votes
3 answers
750 views

Cyclic Take function? [duplicate]

For example, if the functions were named OverTake, then: OverTake[{1, 2}, 5] (* {1, 2, 1, 2, 1} *) (This would be a direct analog of the take functions in the array-processing languages APL and J.) …
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4 votes
Accepted

Plotting a Wavefunction

a = 30; f[x_] := Sqrt[2/a] (3/5 Sin[2 \[Pi] x/a] + 4/5 Sin [(9 \[Pi] x)/a]) Plot[f[x], {x, 0, a}, AxesLabel -> {x, "f(x)"}, PlotStyle -> {Black, Dashed}] Note that you forgot the closing ) in th …
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0 votes
0 answers
56 views

Head of complex sum

Purpose: I'm trying to use functions defined in the form func[{a_Complex, b_Complex}]:= ... … The same problem already arises with complexLine, among the other functions, proffered there. …
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1 vote

Transformation of a simple logic statement

In Mathematica: Reduce[ForAll[{x, y}, x <= y \[Equivalent] x < y + 1], Integers] (* True *) or: Resolve[ForAll[{x, y}, x <= y \[Equivalent] x < y + 1], Integers] (* True *) For a mathem …
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  • 12.1k
10 votes
4 answers
2k views

How make f[{x,y}] evaluate as f[x,y]? [duplicate]

I frequently encounter the situation where I have a function of two real variables defined, e.g.: f[x_, y_] := 9 - x^2 - y^2 But then I need to feed into f not just two numbers but rather a pair, i …
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