I have a function`R1[x_, t_] = -((t^35 x^2)/10333147966386144929666651337523200000000)`;
I use the following command in Mathematica to show the graph of Function

    pic1 = Plot3D[Abs[R1[x, t]], {x, 0, 1}, {t, 0, 1}, PlotRange -> Full, AxesLabel -> {"x", "t"}, AxesEdge -> {{-1, -1}, {-1, -1}, {-1, 1}}, LabelStyle -> Directive[Black, Bold, 14], BoxStyle -> Directive[Thick, Black, 16], BoxRatios -> {1.5, 1.5, 1.5}, ViewPoint -> {-2, -2, 1}, PlotStyle -> Green]
The Image is not shown
[![enter image description here][1]][1]
 
But when I am using the following Function

    R2[x_, t_] = - ((t^35*x^2)/10333147966386144929666651337523200000);
I have just removed three zero from the denominator, Mathematica gives the Image of function using same code

    pic1 = Plot3D[Abs[R2[x, t]], {x, 0, 1}, {t, 0, 1}, PlotRange -> Full, 
      AxesLabel -> {"x", "t"}, AxesEdge -> {{-1, -1}, {-1, -1}, {-1, 1}}, 
      LabelStyle -> Directive[Black, Bold, 14], 
      BoxStyle -> Directive[Thick, Black, 16], 
      BoxRatios -> {1.5, 1.5, 1.5}, ViewPoint -> {-2, -2, 1}, 
      PlotStyle -> Green]
The Image of Second Function is
[![enter image description here][2]][2]


  [1]: https://i.sstatic.net/oTxBPksA.png
  [2]: https://i.sstatic.net/4RaSWbLj.png
How we obtain the Image of 1st Function. I am using Mathematica 13.3.1