Skip to main content
1 of 4
Mr.Wizard
  • 273.1k
  • 34
  • 595
  • 1.4k

According to the comment below your answer I believe this does what you want:

scale    = Sign[#] Log[1 + Abs@#] &;
invscale = Sign[#] (Exp[Abs@#] - 1) &;

ListLinePlot[
 llvaluefull,
 ScalingFunctions -> {{scale, invscale}, Identity}
]

enter image description here

ScalingFunctions works in ListLinePlot in Mathematica 10.0.2, but it is not officially supported. I may not work in earlier versions.

Mr.Wizard
  • 273.1k
  • 34
  • 595
  • 1.4k