SeedRandom[1] n = 10; array = ImageData[RandomImage[1, {n, n}]]; array2 = ImageData[RandomImage[1, {n, n}]]; sa = SparseArray[desired -> 1, Dimensions@array]; newarray = (1 - sa) array2 + sa array; Showing only the `desired` parts of the three matrices: Row[Labeled[MatrixPlot[MapAt[Black &, #, Complement[Tuples[Range[n], {2}], desired]], ImageSize -> 200], #2, Top] & @@@ Transpose[{{array, array2, array2a}, {"array", "array2", "array2a"}}]] [![enter image description here][1]][1] All four methods suggested in answers and comments so far give the same result: array2a = array2b = array2c = array2d = array2; array2a = (1 - sa) array2 + sa array; (Part[array2b, #[[1]], #[[2]]] = Part[array, #[[1]], #[[2]]]) & /@ desired; (* user6014 *) (array2c[[##]] = array[[##]]) & @@@ desired; (* Albert Retey's comment *) array2d = ReplacePart[array2d, Thread[desired -> Extract[array, desired]]]; (* J.M.'s comment *) array2a == array2b == array2c == array2d > True **Timings** ClearAll[timings] timings[m_Integer] := Module[{t1, t2, t3, t4, n = 1000, a, b, c, b2a, b2b, b2c, b2d, sa}, SeedRandom[1]; {a, b} = RandomReal[1, {2, n, n}]; c = RandomSample[Tuples[Range[n], {2}], m]; b2a = b2b = b2c = b2d = b; t1 = First[AbsoluteTiming[sa = SparseArray[c -> 1, {n, n}]; b2a = (1 - sa) b2a + sa a;]]; t2 = First[AbsoluteTiming[(b2b[[##]] = a[[##]]) & @@@ c;]]; t3 = First[AbsoluteTiming[(Part[b2c, #[[1]], #[[2]]] = Part[a, #[[1]], #[[2]]])&/@c;]]; t4 = First[AbsoluteTiming[b2d = ReplacePart[b2d, Thread[c -> Extract[a, c]]];]]; {m, t1, t2, t3, t4, b2a == b2b == b2c == b2d}] tr = timings /@ {100, 500, 5000, 50000, 100000, 300000}; backgroundrule = # -> Item[#, Background -> Yellow] & /@ Min /@ tr[[All, 2 ;; 5]]; headers = {{"Length@desired", "method", SpanFromLeft, SpanFromLeft, SpanFromLeft, " b2a==b2b==b2c==b2d "}, {SpanFromAbove, " SparseArray ", " ApplySetPart ", " MapSetPart ", " ReplacePart ", SpanFromAbove}}; Grid[Join[headers, timingresults /. backgroundrule], Dividers -> All, Alignment -> {Center, Center}] [![enter image description here][2]][2] [1]: https://i.sstatic.net/H8x39.png [2]: https://i.sstatic.net/h1kFw.png