I have a function,
f[dist_, samp_]:=somework[dist, samp]
that I want to return Null
or zero if passed a null distribution. I can't find a way to test for a difference between Null
and Data distribution: none of ===
, =!=
, SameQ
and ==
can identify them.
How can I tell if I'm being passed a Null
value to handle it correctly?
f[dist_, samp_]:=something[dist, samp] /; TrueQ[dist==DataDistribution]
Seems to be close to what I want.
EDIT: Edited for some clarity.
Here's my function. If probKern is a Null, I want to return a Null, otherwise, I want to calculate the PDF for the sample, with the distribution. I can't quite get a handle on matching the types to make this work though.
calcPDF[probKern_, samp_] :=
Null /; TrueQ[probKern != DataDistribution]
calcPDF[probKern_Symbol, samp_] :=
PDF[probKern, samp] /; TrueQ[probKern == DataDistribution]
edit: Okay, I'm still having trouble with this. Here's what I have:
calcPDF[probKern_DataDistribution, samp_] := PDF[probKern, samp]
calcPDF[Except[DataDistribution, probkern?DistributionParameterQ],
samp_] := -1
calcPDF[_] := $Failed
Given a data distribution and a value it works fine. `In[38]:= calcPDF[data, 3]
Out[38]= 0.007500611755`
Given two numbers, it produces the symbolic value, rather than the -1 I was expect. (The -1 is just a placeholder)
`In[39]:= calcPDF[3, 3]
Out[39]= calcPDF[3, 3] `