FYI the algorithm for those letters is simply:
Say each of the six lettes is one unit width.
Draw a vertical line on the left of the screen.
Take a random step to the right $0.03$ to $0.1$ units (just tune these two figures to get the look of the original; it's about $3\rightarrow10$) and draw another vertical line.
You'll end up with roughly $100$ vertical lines across the screen.
When I say "vertical line" make them say $70\%$ (slightly randomize that, not too much) the height of the screen; and just randomize their position up down down the remaining $30\%$.
For the other lines, it's remarkably simple,
Take any random point at all on the surface of the text.
Take any random angle.
Take a random length from $30\%$ to about $60\%$ the height of the screen.
Simply repeat step (3) until you get the density you want.
It's that simple, that's all there is to it.
Problems in the answers already presented above (that is to say differences from the final look of the given samples) are:
i) Y'all forgot the vertical lines.
ii) There's no need at all to go from one point in the text mesh to another point in the text mesh. Simply follow the recipe at 3-4-5 above.
Note: in (4) above it's possible they have biased the angle to something like "any angle $-70°$ to $+70°$" rather than just "any angle". Just try it.
PS Couldn't be bothered adding yet another network account for this! Cheers!
