While I would actually use list[[All, All, 2]]
as I have yet to find a case where that is not fastest, you could also do this with Apply
:
Apply[#2 &, list, {2}]
While I would actually use list[[All, All, 2]]
as I have yet to find a case where that is not fastest, you could also do this with Apply
:
Apply[#2 &, list, {2}]