# Questions tagged [simplifying-expressions]

Questions on manipulating complicated expressions and making them look simpler using Simplify, FullSimplify and Reduce.

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### How to 'define' value in Assumptions but not let Simplify replace it?

I want to let Simplify know the exact value of a symbol, to resolve logical statements, but don't want it to actually replace it. For instance, I would like ...
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### Did Mathematica make a mistake or was it me?

I'm having a little trouble with Mathematica. There are two expressions that should be equal over a given region. Each of which consists of three terms that should be equal individually: term1 of ...
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### Difference between Assuming[] and Refine[]

I'm trying to find the limit of a root. I've found that the limit is undefined if I use Refine[] ...
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### Simple Question: Cut Number in Transfer function

Given transfer function: $W=\frac{10 (s+100)}{2 s^4+219 s^3+1909 s^2+900 s+1000}$ W=(1000 + 10 s)/(1 (1000 + 900 s + 1909 s^2 + 219 s^3 + 2 s^4)) Which command to ...
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### Simplification based on Kronecker Product Properties

I am trying to simplify some algebraically intensive expressions that involve inverses and Kronecker products. One simple example of such an expression is (1) \quad \quad \quad Z'(I_n\otimes\Sigma+Z\...
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### How to refine polynomial which has a constraint condition to perfect square?

The expression : 1 + 4 p2^4 + 4 p2^2 (-1 + p1^2 - p3^2) - 4 p3^2 (-1 + p1^2 + p3^2) has a constraint condition: ...
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### Why is Mathematica returning Abs[-1+x] even with assumption x<1?

With the following Simplify[Abs[-1 + x], {-1 + x < 0}], I expect Mathematica to return 1-x, but it instead gives the same <...
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### Mathematica cannot simplify a rather simple expression with only one term

I run this code on Mathematica 11.2, Simplify[1/x^2,Assumptions->(1/x^2==1)] and hope to get 1, but Mathematica returns me ...
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### Formal substitution of exponential factors in an expression

Assume that we have some complex algebraic expression, like Exp[(a t + b s)/w] ( t Exp[ q t] w + q Exp[q s] Exp[-2 s] + a^2 Exp[3 s] + s t + 1 ) Now, this is just ...
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### How to get rid of {{ }} from scalars?

I am confronted with the situation where a scalar appear within curly brackets like a = {{2}} (as example) and the subsequent operation involves multiplying ...