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3 votes
1 answer

What tools does Mathematica have for solving indefinite integrals?

I haven't used Mathematica regularly in about 15 years, so I'm a bit out of date on what the latest tools are for indefinite integration. I have Mathematica 11 on my computer. through searching online,...
Machinus's user avatar
0 votes
0 answers

Integrate function differing from RUBI's Int function in version 13.3.0

I had Mathematica Version 12.3.1 Student Edition and Integrate and RUBI's Int functions produced the same answers for my purposes with good results. I updated my version to 13.3.0 Student Edition and ...
Tom00496's user avatar
1 vote
0 answers

Problem installing Rubi on Mac OS X ARM

I installed the Rubi package by using ResourceFunction["GitHubInstall"]["RuleBasedIntegration","Rubi"] but when I use it, it only ...
dcmpsr's user avatar
  • 53
4 votes
1 answer

Mathematica vs Rubi --- integrate $f(x,y) = x \sin^2 x + a x y$ --- Mathematica got this round? [closed]

Consider the function: $$ \begin{equation} f(x,y) = x \sin^2 x + a x y \end{equation} $$ with $a$ being a constant. We want to do the indefinite integral over $x$ and then over $y$. We do that using <...
user avatar
2 votes
0 answers

Understanding results from Rubi integrator

I am just starting out with Mathematica and more specifically Rubi. I just tried to integrate the following. ...
Sarthak Choudhury's user avatar
2 votes
0 answers

How to check Rubi version number in use? [closed]

On my Mathematica 11.2 Windows system I have Rubi version 4.15 installed manually and version 4.16 installed with the paclet installation procedure. So these two versions reside in totally different ...
Roland Salz's user avatar
0 votes
0 answers

Rubi/Mathematica gives different values for the same integrand

Consider this integral: $$ \int_0^\pi d\theta \sin\theta\, {1 \over \gamma^q}\left((1-\gamma^2)^2\sqrt{1 \over 1-\left(1-(1-\gamma^2)^4\right)\cos^2\theta} - 1\right)^q $$ for $0\leq \gamma < 1$. ...
Fluid's user avatar
  • 119
2 votes
1 answer

Problem calling function defined with HoldFirst

V 12.1 on windows. I am trying to use nice function from a recent post How to directly get the TeXForm of each steps from Rubi? ps. to run MWE code below, requires Rubi package, which if you do not ...
Nasser's user avatar
  • 146k
6 votes
1 answer

How to directly get the TeXForm of each steps from Rubi?

It's easy to read the steps from Rubi, but kind of tired to copy it out of as $\LaTeX$. That's what now I do: Int[x Sin[x], x]//Steps For example,click one step, ...
AsukaMinato's user avatar
  • 9,988
5 votes
1 answer

Problem with Rubi` and paclets in Version 12.1?

A recent Quora post on computing an integral used the Integral Calculator, the interface and display of which I found somewhat impressive. So I thought that I'd try the same computation in Rubi so as ...
TheDoctor's user avatar
  • 2,870