Linked Questions

12 votes
1 answer
1k views

1/x integration giving 0 instead of infinity [duplicate]

I stumbled across the fact this integral: Integrate[1/y, {y, 0, 1}, GenerateConditions -> False] returns 0 Anybody ...
danchus's user avatar
  • 121
11 votes
1 answer
449 views

What exactly does GenerateConditions do?

Consider for example this strange behavior: Integrate[1/x, {x, 0, Infinity}, GenerateConditions -> False] (*0*) I'd also like to know the difference between <...
Emerson's user avatar
  • 1,217
11 votes
1 answer
633 views

FourierSeries for rational function looks wrong

Bug introduced in Version 8 or earlier, and persisting through 12.1. I have the following code: ser[x_] = FourierSeries[(π^2 + a)/(3 x^2 + a), x, 10] // N // Chop ...
Ruslan's user avatar
  • 7,172
9 votes
2 answers
430 views

Why does Mathematica say $\int_0^1\int_0^1\int_0^1\frac{1.0}{xyz}\,dz\,dy\,dx=0$?

Mathematica 9 says that $\int_0^1\int_0^1\int_0^1\frac{1.0}{xyz}\,dz\,dy\,dx=0$ and $\int_0^1\int_0^1\int_0^1\frac{1}{xyz}\,dz\,dy\,dx=0$. ...
Steve Kass's user avatar
6 votes
2 answers
273 views

surprising behavior of `Sum`

Compare the following. (The option specified is the default value; just to be explicit.) ...
Alan's user avatar
  • 13.8k
3 votes
3 answers
1k views

Want to eliminate conditions from result of Integrate

This is my first time using Mathematica for the purpose of solving complex integrals. I have to compute few complex integrals which have many coefficients. For example, $$\int_0^\infty \frac{k^2\, ...
filipmor's user avatar
2 votes
1 answer
121 views

integral gets solved by changing sign in front of a real constant?

I am solving the following integral in Mathematica ...
cleanplay's user avatar
  • 690
2 votes
1 answer
300 views

Generate conditions seems to not work [closed]

I am trying to compute the following integral Integrate[E^(I*k*Omega*t), {t,0,T}, GenerateConditions->True] for which Mathematica returns ...
Jommy's user avatar
  • 121
2 votes
1 answer
255 views

Integrate and ConditionalExpression Output

I am integrating some difficult functions and using the conditional output to place bounds on parameters to ensure integrability, but it seems that not all of the conditions are being returned. The ...
Freakalien's user avatar
1 vote
1 answer
165 views

Mathematica 11: Mellin transform conditions?

Consider the expression fun = 1/(y^2-1)^a; If I do the Mellin Transform explicitly, I get a result that involves a few conditions on the parameters ...
Kagaratsch's user avatar