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### Making time differentials look like the textbook [duplicate]

I need to have time differentials to look like the 'textbook'. My code is Dt[x y^2] /. {Dt[x] -> dx/dt, Dt[y] -> dy/dt} which gives the output ...
61 views

### Getting Mathematica to supply derivatives in standard format [duplicate]

I will like to use the results of Mathematica outputs in formatted text for students. However, I do not know how to get rid of the variable arguments and the use of raised indices to indicate ...
31 views

### Using Format to create a notation for derivatives [duplicate]

I want to create a new function that I called HD to give a visual way to see the derivatives. For example: The objective is apply the function ...
28k views

366 views

### Customizing display of partial differential equations

I am manipulating partial differential equations symbolically, and would like to get the easily readable form $\rho \frac{\partial v}{\partial t}$, leaving variables implicit. Based on suggestions ...
2k views

### How to work with differentials explicitly?

When working with differential equations with independent (e.g. t )and dependent (e.g., x[t]) variables Mathematica expresses ...
1k views

### How to preserve the order of terms in the output

Is there a way in which mathematica can preserve the order of operations while it evaluates an expression?, for instance: In my short example ...
1k views

### Typesetting - entering derivative in traditional form

I am trying to work out how I enter a differential in standard notation? I am familiar with using D, but everything I have tried to enter a differential has failed. ...
328 views

### Notation for implicit derivative

Consider the following line of code: D[x == y^3 + x y, x, NonConstants -> y] The output would be: ...
314 views

### How to define a rule to simplify the notation for derivatives of chain rule?

Suppose that $u(x,y)$ is a function, and $x=r \cos t$, $y= r \sin t$, then we can define a new function $v(r,t):=u(x,y)$ with $x,y$ replaced by the above equations. It is quite easy to compute $v$'s ...