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When defining a graph whose vertices are sets e.g. the Kneser graph, how does Mathematica interpret the vertices?

I am having trouble highlighting vertices when I define vertices with sets, but for some reason highlighting edges creates no problem:

HighlightGraph[Graph[{{1, 2} <-> {3, 4}}], {{1, 2} <-> {3, 4}}]

This creates an edge with the edge highlighted, as expected. However

HighlightGraph[Graph[{{1, 2} <-> {3, 4}}], {1,2}]

does not highlight the vertex corresponding to {1,2}.

I originally had a colleague help write a program to construct the general Kneser graph. However, when using FindIndependentVertexSet, it lists the correct vertices (sets), but when using HighlightGraph, it doesn't highlight anything; using FindHamiltonianCycle, I can highlight the cycle though.

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    – Dr. belisarius
    Nov 16, 2015 at 21:02

1 Answer 1

Reset to default
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Probably a bug.
You may use this alternative syntax:

g = Graph[{{1, 2} <-> {3, 4}}]; 
SetProperty[{g, {{1, 2}}}, GraphHighlight -> True]

Mathematica graphics

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  • $\begingroup$ Unfortunately, this method, which works for me a few hours ago (on my local Mathematica 10.2 install), fails now. It return $Failed. $\endgroup$
    – user202729
    Jun 11, 2017 at 4:06

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