When a pure function accesses the first element of itself, 0 is output. What is the logic behind this, or is there any?


The FullForm of #0[[1]] & is

Function[Part[Slot[0], 1]]

So when this function is called with no arguments, I believe what happens is that Slot[0] does not evaluate, and then you take the first part of Slot, which is 0. Here it seems that Slot behaves as any other head.

  • 6
    $\begingroup$ No need to believe, you can check :) #0[[1]] &[] // Trace $\endgroup$ – Kuba Nov 16 '15 at 14:47

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