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I want to define an integral function which depends on a system of ODE and is also used to NDSolve the ODEs.

Tc = Sum[c[i]];

D[c[i], t] == r[i] c[i] (1 - Tc/k) - d[i] c[i]

where i = 1,...,n

Basically, I want to evaluate Tc at a given t value, before solving the differential equation for c[i] so that the code uses this value for NDSolve.

r, k and d are known parameters. c[i] needs to be calculated and thus Tc which is a summation of all c[i]s, at a give time t, is also unknown.

Thanks in advance :)

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  • $\begingroup$ Your question is not clear enough for me. Could you try to define your goal more carefully and which elements are known / unknown? $\endgroup$ – Dr. belisarius Oct 27 '15 at 14:10
  • $\begingroup$ r, k and d are known parameters. c[i] needs to be calculated and thus Tc which is a summation of all c[i]s, at a give time t, is also unknown. $\endgroup$ – VitalSigns Oct 27 '15 at 16:47
  • $\begingroup$ Do only c[i] == c[i][t] and Tc == Tc[t] depend on on t? Looks a bit like the replicator equation. Just enter the equations as you normally would for NDSolve -- doesn't that work? Or define Tc[t_] = Sum[c[i][t], {i, n}] outside NDSolve and use Tc[t] inside NDSolve. $\endgroup$ – Michael E2 Oct 27 '15 at 16:57
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  • $\begingroup$ @MichaelE2 : Your solution worked too. Thanks! I defined Tc[t] == Sum of all c[i] within the NDSolve bracket and it worked. If i define it outside the bracket as Tc= Tc[t] == Sum of all C[i] and then use Tc in NDSolve bracket it doesn't work. weird ... I cant understand why? $\endgroup$ – VitalSigns Nov 3 '15 at 13:49
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Perhaps

n = 5;
cc = Array[c[#] &, n];
Tc = Sum[c[i][t], {i, n}];
r = RandomInteger[{1, 10}, n];
d = RandomInteger[{1, 10}, n];
k = RandomInteger[{1, 100}];
initcon = Table[c[i][0] == RandomInteger[{0, 10}], {i, n}]

sol = NDSolveValue[
      Join[Table[D[c[i][t], t] == r[[i]] c[i][t] (1 - Tc/k) - d[[i]] c[i][t], {i, n}],
           initcon], 
      cc, {t, 0, 10}]

Plot[Through[sol[t]], {t, 0, 10}, Evaluated -> True]

Mathematica graphics

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