# Plot $\arg(z)$ in an Argand diagram and display the angle

I'd like to ask you about the way to show the $$\arg(z)$$ annotation about the angle. My point is to show $$\frac{2\pi}{3}$$ and $$\frac{5\pi}{6}$$ on the image.

What I mean:

(source: brocku.ca)

Is there any way to achieve similar effect in Mathematica?

My code:

    Show[%6, Axes -> True, Method -> {"ScRegionPlot[
Pi/4. <= Arg[x + I y] <= Pi, {x, -1, 1}, {y, -.1, 1},
GridLines -> {{-.15}, {0}},
PlotPoints -> 60, Show[%6,Axes\[Rule]True,Method\[Rule]{" \
ScRegionPlot[
Norm[x + I y + .15] < 0.6 &&
Pi/4. <= Arg[x + I y] <= Pi, {x, -1, 1}, {y, -.1, 1},
AspectRatio ->
Automatic] alingFunctions "\[Rule]None," \
TransparentPolygonMesh "\[Rule]True}]
AspectRatio -> Automatic]alingFunctions" -> None,
"TransparentPolygonMesh" -> True}]


• Graphics[Disk[{0, 0}, 1, {2 π/3, 5 π/6}], Axes -> True]? Commented Oct 17, 2015 at 13:58
• Thank you but I wanted to print the angle on the image. Both of them. Another example: physics.brocku.ca/PPLATO/h-flap/math3_3f_2.png Commented Oct 17, 2015 at 14:00
• Try adding Text[#, {Cos[#], Sin[#]}, {1, -1}] & /@ {2 π/3, 5 π/6} Commented Oct 17, 2015 at 14:04
• @terry_8 Maybe you want to try Text. Commented Oct 17, 2015 at 14:05

roots = z /. Solve[z^3 == 1, z];
pts = {Re[#], Im[#]} & /@ roots;
args = Arg /@ Cases[roots, _?(Im[N[#]] != 0 &)];

Module[{pr = 1.25, radius = {1/4, 3/8}},
Graphics[{
Thick,
Arrow[{{-pr, 0}, {pr, 0}}],
Arrow[{{0, -pr}, {0, pr}}],
Text[Style[Subscript[z, 0], 18, Bold],
pts[[1]], {0, -2}],
Text[Style[Subscript[z, 1], 18, Bold],
pts[[3]], {0, -2}],
Text[Style[Subscript[z, 2], 18, Bold],
pts[[2]], {0, 2}],
{
Circle[{0, 0}, #[[1]], {0, #[[2]]}],
Text[Style[#[[2]], 14, Bold], #[[1]]*
Through[{Cos, Sin}[#[[2]]/2]],
{-1.25, -Sign[#[[2]]]}]} & /@
AbsolutePointSize[10],
Point[pts],
AbsoluteDashing[{10, 10}],
Line[{{0, 0}, #}] & /@ pts},
Axes -> True,
Ticks -> {Range[-1, 1, 1/2], Range[-1, 1, 1]},
TicksStyle -> Directive["Label", 14],
PlotRange -> {{-pr, pr}, {-pr, pr}},
AxesLabel -> (Style[#, 14, Bold] & /@ {Re, Im})]]


A question on plotting complex numbers begs for an answer that directly uses complex numbers rather than requires pulling the complex numbers apart into real and imaginary parts. Such an answer is allowed by David Park's Presentations( add-on (https://home.comcast.net/~djmpark/DrawGraphicsPage.html):

   <<Presentations

roots = z /. Solve[z^3 == 1, z];
args = Arg /@ Select[roots, ! Element[#, Reals] &];

With[{rng = 1.25, radii = {1/4, 3/8}, arcOffset = 1.4},
Draw2D[{
Thick,
(*arrow axes *)
ComplexArrow[{-rng, rng}], ComplexArrow[{-rng I, rng I}],

(* labeled arcs *)
ComplexCircle[0, First@#, {0, Last@#}] & /@
ComplexText[Last@#,
ComplexPolar[ arcOffset First@#, Last@#/2], {-1, 0}] & /@

(* lines to roots *)
Dashing[0.035],
ComplexLine[{0, #}] & /@ Rest@roots,

(* labeled roots *)
PointSize[0.025], ComplexPoint /@ roots,
ComplexText[Sequence @@ #] & /@
Transpose[{Style[#, 18] & /@ {Subscript[z, 0], Subscript[z, 2],Subscript[z, 1]},
roots, {{0, -2}, {0, 2}, {0, -2}}}]
},
PlotRange -> rng,
Axes -> True, AxesLabel -> {Re, Im},
Ticks -> {Range[-1, 1, 1/2], Range[-1, 1, 1]},
TicksStyle -> Directive["Label", 14, FontWeight -> "Medium"],
BaseStyle -> Directive[14, Bold]
]
]


Here's the same thing decorated a bit with use of color, etc.:

   With[{rng = 1.25, radii = {1/4, 3/8}, arcOffset = 1.4},
Draw2D[{
Thick,
(*arrow axes *)
{Gray, ComplexArrow[{-rng, rng}], ComplexArrow[{-rng I, rng I}]},

(* labeled arcs *)
{Legacy@SeaGreen, ComplexCircle[0, First@#, {0, Last@#}] & /@
ComplexText[Last@#,
ComplexPolar[ arcOffset First@#, Last@#/2], {-1, 0}] & /@

(* lines to roots *)
{Dashing[0.035], Legacy@BrownOchre,
ComplexLine[{0, #}] & /@ Rest@roots},

(* labeled roots *)
ComplexCirclePoint[#, 5, Black, Legacy@CadmiumOrange] & /@ roots,
ComplexText[Sequence @@ #] & /@
Transpose[{Style[#, 18] & /@ {Subscript[z, 0], Subscript[z, 2],Subscript[z, 1]},
roots, {{0, -2}, {0, 2}, {0, -2}}}]
},
PlotRange -> rng,
Axes -> True, AxesLabel -> {Re, Im},
Ticks -> {Range[-1, 1, 1/2], Range[-1, 1, 1]},
TicksStyle -> Directive["Label", 14, FontWeight -> "Medium"],
BaseStyle -> Directive[14, Bold],
Background -> Lighter@Legacy@Linen,
PlotLabel -> "The cube roots of unity"
]
]
`