I want to take an expression of the form


and have an output of something like


If I do the replacement


this ends up multiplying the two lists together, which I don't want. How can I do this? It also needs to be for an arbitrary number of p[i,j]


closed as off-topic by C. E., MarcoB, m_goldberg, Daniel Lichtblau, user9660 Oct 13 '15 at 5:12

This question appears to be off-topic. The users who voted to close gave this specific reason:

  • "This question arises due to a simple mistake such as a trivial syntax error, incorrect capitalization, spelling mistake, or other typographical error and is unlikely to help any future visitors, or else it is easily found in the documentation." – C. E., MarcoB, m_goldberg, Daniel Lichtblau, Community
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  • 8
    $\begingroup$ p[1, 2] p[3, 4] /. {Times | p -> List} $\endgroup$ – Dr. belisarius Oct 12 '15 at 18:16
  • 2
    $\begingroup$ List @@@ List @@ (p[1, 2] p[3, 4]) $\endgroup$ – march Oct 12 '15 at 20:22

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