0
$\begingroup$

Now I am working on something like this:

helix[a_, b_][t_] := {a*Cos[t], a*Sin[t], b*t}    
listept1 = Table[helix[1, 0.35][t], {t, 0, 4 Pi, .25}];
listept2 = Table[helix[0.25, 0.35][t], {t, 0, 4 Pi, .25}];
mapdecalgarde = Map[{0, 0, 0.5} + # &, {listept1}, {2}];
exterieurSup1 = Map[{0, 0, 0.1} + # &, listept1];
mapdecalgarde1 = Map[{0, 0, 0.5} + # &, listept1];
Listedepointgardecorps1 = 
Flatten[{{mapdecalgarde1}, {exterieurSup1}}, 1];
ptsGarCor1 = Transpose[Listedepointgardecorps1];
ligneGardeCor1 = Map[Line, ptsGarCor1];
barriere = Graphics3D[{Opacity[0.25], RGBColor[1, 3, 0], Tube[ptsGarCor1]}]

and simple rods I want to substitute with this particular shape:

Graphics3D[{CapForm["Round"], Tube[{{0, 100, 0}, {100, 300, 0}, {300, 300, 100}}, 40]},  Boxed -> False, PlotRange -> All]

in this orientation:

enter image description here

so it freely rotates around (let say) Z direction where XY plane alongside the twofold symmetry axis.

$\endgroup$
  • $\begingroup$ What is your question exactly? $\endgroup$ – march Sep 23 '15 at 22:48
  • $\begingroup$ How to substitute ordinary rods with bent-core rods (on spiral)? $\endgroup$ – ATomek Sep 23 '15 at 23:15
  • $\begingroup$ Your helix[ ] lacks the definition $\endgroup$ – Dr. belisarius Sep 23 '15 at 23:50
  • $\begingroup$ I have edited the code and added definition of helix[] (which I have previously forgot to include). $\endgroup$ – ATomek Sep 23 '15 at 23:58
  • $\begingroup$ Like this? $\endgroup$ – Michael E2 Sep 24 '15 at 0:03
3
$\begingroup$

Are you wanting the kinks to point directly away from the z-axis? If not I'll remove this answer.

carat[{{x_, y_, z1_}, {x_, y_, z2_}}] := 
 Translate[
  Rotate[Translate[
    Tube[{{x, y, z1}, {x + (z2 - z1)/4 Sqrt[3/7], y, (z1 + z2)/2}, {x, y, z2}}, 
     (z2 - z1)/10], {-x, -y, 0}], π + ArcTan[x, y], {0, 0, 1}], {x, y, 0}]

Graphics3D[{CapForm["Round"], Opacity[0.25], RGBColor[1, 3, 0], 
  carat /@ ptsGarCor1}, Boxed -> False]

enter image description here

$\endgroup$
  • $\begingroup$ I want to recreate something like this Link $\endgroup$ – ATomek Sep 24 '15 at 10:02
  • $\begingroup$ @ATomek as far as I can tell, that's what I think my solution does. $\endgroup$ – Chip Hurst Sep 24 '15 at 15:44

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.