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I understand why Mathematica doesn't the support the [ character in symbol names, but it should be escapable in some way, like non-printable characters are in strings using \. A bigger problem is that a large number of Unicode characters are also not allowed in symbol names, and some of them for no obvious reason.

Is there a good way to escape such characters? Ideally, it should be broadly usable in arbitrary Mathematica code without requiring further special handling of the escaped symbol names.

I'm thinking something like the following:

Replace[a$multiply$[b[c, d]], 
 head_[x___] :> $[
        StringReplace[ToString@head, {"$multiply$" :> "*"}]][x], {0, 
  Infinity}]
Improve this question
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  • $\begingroup$ I'm voting to close this question as off-topic because this is not a question but merely a rant about how the OP would like to change the behavior of Mathematica $\endgroup$
    – m_goldberg
    Sep 10, 2015 at 2:57
  • $\begingroup$ @m_goldberg But what if I can patch it to something like a posted used the dollarsign character? I'll let you close it, but I will probably repost it once I get a somewhat working solution. $\endgroup$
    – William
    Sep 10, 2015 at 3:13
  • $\begingroup$ @M_goldberg If I get one more downvote I'm probably going to delete it for now. $\endgroup$
    – William
    Sep 10, 2015 at 3:18
  • 4
    $\begingroup$ While allowing arbitrary characters in symbols is perhaps not a good idea (could lead to ambiguities in interpretation), I for one do not see any "rant" here, so +1 to offset down-votes I do not think warranted. $\endgroup$
    – ciao
    Sep 10, 2015 at 3:47
  • $\begingroup$ I edited your question to try to make it more accessible, since I had to read carefully to discover what you were really getting at and understand that it is a valid and useful thing to want. If you do not like the edits, please roll back as appropriate, but in my opinion it is a more idiomatic question when posed this way. You also have my upvote, not for offsetting reasons but because it is a good question in its essence. $\endgroup$
    – Oleksandr R.
    Sep 10, 2015 at 23:00

1 Answer 1

Reset to default
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The following is in the right direction if you include the answer to invalid Symbol characters also. 

opts = {"$divide$" :> "/", "$backslash$" :> "\\", "$period$" :> ".", 
   "$tilde$" :> "~", "$backtick$" :> "`", "$exclaim$" :> "!", 
   "$at$" :> "@", "$number$" :> "#", "$dollar$" :> "$", 
   "$percent$" :> "%", "$caret$" :> "^", "$amp$" :> "&", 
   "$multiply$" :> "*", "$parenleft$" :> "(", "$parenright$" :> ")", 
   "$underscore$" :> "_", "$dash$" :> "-", "$plus$" :> "+", 
   "$equal$" :> "=", "$barleft$" :> "[", "$barright$" :> "]", 
   "$bracketleft$" :> "{", "$bracketright$" :> "}", "$colon$" :> ":", 
   "$semicolon$" :> ";", "$singlequote$" :> "'", 
   "$doublequote$" :> "\"", "$lessthan$" :> "<", "$comma$" :> ",", 
   "$period$" :> ".", "$slash$" :> "/", "$question$" :> "?", 
   "$space$" :> " ", "$n$" :> "\n", "$r$" :> "\r"};
opts = Join[
   Drop[Quiet[
     Cases[Symbol[FromCharacterCode[#]] & /@ Range[0, 16^4 - 1], 
      Symbol[z__] -> (StringJoin@
          Flatten@Join[{"$", IntegerString[ToCharacterCode[z], 16, 4],
              "$"}] -> z)]], 1], opts];
Replace[a$multiply$[b$underscore$[c, d]], 
 head_[x___] :> $[StringReplace[ToString@head, opts]][x], {0, 
  Infinity}]

If you would like to display it in a pretty form you can do the following.

ReplaceRepeated[
 ToBoxes[FullForm@Ti$at$mes[{a}, Rational[1, -2], "test"]][[1, 
   1]], {RowBox[{b_String, "[", x___String, "]"}] :> 
   StringJoin[{StringReplace[b, opts], "[", x, "]"}], 
  RowBox[{b___String}] :> StringJoin[{b}]}]
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