Solve::nsmet system equations [closed]

A = Exp[-I*x] - Exp[-I*fi] Exp[I*x];
B2 = a21 + Exp[-I*x]*a20;
C2 = Cos[Theta] (a10 - a20);
DD = Exp[-2 I*fi] Exp[-I*x] - Exp[-I*fi] Exp[I*x];
B1 = Exp[-2 I*fi] (a11 - a10*Exp[-I*x]);
C1 = Cos[Theta] (a00 - a20);
EE = Exp[-I*fi] Exp[-I*x] - Exp[I*x];
B0 = Exp[-I*fi] (a01 - a00*Exp[-I*x]);
C0 = Cos[Theta] (a20 - a10);
Solve[
F2 == (B2 + C2 + Cos[Theta]*(F0 - F1))/A &
F1 == (B1 + C1 + Cos[Theta]*(F2 - F0))/D &
F0 == (B0 + C0 + Cos[Theta]*(F1 - F2))/E,
{F1, F2, F0}]


Solve::nsmet: This system cannot be solved with the methods available to Solve. >>

What's the problem?

closed as off-topic by Michael E2, xyz, MarcoB, Bob Hanlon, m_goldbergSep 10 '15 at 2:53

This question appears to be off-topic. The users who voted to close gave this specific reason:

• "This question arises due to a simple mistake such as a trivial syntax error, incorrect capitalization, spelling mistake, or other typographical error and is unlikely to help any future visitors, or else it is easily found in the documentation." – Michael E2, xyz, MarcoB, Bob Hanlon, m_goldberg
If this question can be reworded to fit the rules in the help center, please edit the question.

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• This error message means that Solve does not know how to solve this set of equations. Indeed, many equations do not have closed-for solutions. Would it meet your needs to obtain a numerical answer? – bbgodfrey Sep 10 '15 at 1:38
• I think you want And instead of Function -- i.e, && instead of &. – Michael E2 Sep 10 '15 at 1:45
• I think you want DD in that denominator and not D – Bill Sep 10 '15 at 2:26

Rewriting your code with & corrected to && and with parameters given in a more consistent manner

B0 = Exp[-I*fi] (a01 - a00*Exp[-I*x]);
B1 = Exp[-2 I*fi] (a11 - a10*Exp[-I*x]);
B2 = a21 + Exp[-I*x]*a20;
C0 = Cos[Theta] (a20 - a10);
C2 = Cos[Theta] (a10 - a20);
C1 = Cos[Theta] (a00 - a20);
AA = Exp[-I*x] - Exp[-I*fi] Exp[I*x];
DD = Exp[-2 I*fi] Exp[-I*x] - Exp[-I*fi] Exp[I*x];
EE = Exp[-I*fi] Exp[-I*x] - Exp[I*x];

Short[
Solve[
F2 == (B2 + C2 + Cos[Theta]*(F0 - F1))/AA &&
F1 == (B1 + C1 + Cos[Theta]*(F2 - F0))/DD &&
F0 == (B0 + C0 + Cos[Theta]*(F1 - F2))/EE,
{F1, F2, F0}],
6]


gives the following solution: