Solve the simultaneous equations:
70-T=7a
T-40=4a
By multiplying both sides of the equations by a factor and shifting the terms I transformed them into the following form:
-28a-4T=-280
-28a+7T=+280
Further simplification results in a single equation as follows:
-11T=-560
So, T
is a recurring number, which I know cannot be correct, so where am I going wrong?
T=560/11
. Then substitute this into either of the first two equations to solve fora
. $\endgroup$