Is it possible in Histogram3D to substitute frame ticks text labels and have the layout in x-y plane?

Starting with a Histogram3D such as

enter image description here

Then combining with additional Graphics3D text elements, eg:

 Text[Style[lbl, Medium], {-1, pos + 1/2, 0}, {1, 0}, {1.5, -1}]

Text orientation changes with histogram rotations, and they look awful. Any ideas?

  • 2
    $\begingroup$ I imagine you might need to Rasterize your labels, then use them as a Texture on a Polygon. But I don't know how you might show them outside the box (short of drawing your own box and axes). $\endgroup$ – wxffles Aug 2 '12 at 2:01

Here's something to get you started, based on wxffles' comment:

Generate a Histogram3D:

histo = Histogram3D[RandomVariate[UniformDistribution[{0, 10}], {500, 2}], 
ChartElementFunction -> "GradientScaleCube"];

Generate some labels and Rasterize them with a specific height:

labels1 = Rasterize[Style[Column[DictionaryLookup["a*"][[;; 10]], Dividers -> All], 
FontFamily -> "Calibri"], ImageSize -> {{10^6}, {300}}, RasterSize -> 300];

labels2 = Rasterize[Style[Column[DictionaryLookup["z*"][[-10 ;;]], Dividers -> All], 
FontFamily -> "Calibri"], ImageSize -> {{10^6}, {300}}, RasterSize -> 300];

Calculate the width of the polygons to maintain the aspect ratio of the labels (in this case the polygon height will be 10 as there are 10 bins):

w1 = ImageDimensions[labels1][[1]]*10./300;
w2 = ImageDimensions[labels2][[1]]*10./300;

Put it all together:

Show[histo, Graphics3D[{
Texture[labels1], Polygon[{{-w1-1,0,0},{-1,0,0},{-1,10,0},{-w1-1,10,0}},
VertexTextureCoordinates -> {{0,0},{1,0},{1,1},{0,1}}],
Texture[labels2], Polygon[{{0,11+w2,0},{0,11,0},{10,11,0},{10,11+w2,0}},
VertexTextureCoordinates - >{{0,0},{1,0},{1,1},{0,1}}]
}], PlotRange -> All, Boxed -> False, BoxRatios -> {1,1,0.4}, Axes -> {False, False, True},
FaceGrids -> {{{0,0,-1},{Range[0,10],Range[0,10]}}}]

enter image description here

| improve this answer | |
  • $\begingroup$ Very nice Simon. Without something like OpenGL this will do. $\endgroup$ – alancalvitti Aug 4 '12 at 16:21

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