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Background: I partition images to polygons ( squares ) and color them with VertexColors. I want to use a minimal number of polygons while still showing a clear resemblance of the original image. - Some images need more squares in the centre than along the edges ( i.e. portraits ). I want to create an ImagePartition type-of-function that uses a finer grid closer to the middle of a picture.

For example:

 1-1 1-2 1-3 1-4 1-5
 2-1 .           2-5
 3-1 .           3-5
 4-1 .           4-5
 5-1 5-2 5-3 5-4 5-5
 ( 5-by-5 )

The missing part

 2-2 2-3 2-4
 3-1 3-2 3-3
 4-1 4-2 4-3

is replaced with pieces from a 10-by-10 partitioning, i.e. 2-2 by:

 3-3 3-4
 4-3 4-4

and so on, until 4-3 is replaced with

  7-7 7-8
  8-7 8-8

from the 10-by-10 partitioning.

Finally 3-2 or ( 5-5, 5-6 / 6-5, 6-6 ) is replaced with the results from a 20-by-20 partitioning.

 9-9  9-10  9-11   9-12
 10-9 10-10 10-11 10-12
 11-9 11-10 11-11 11-12
 12-9 12-10 12-11 12-12.

In the case of 6-by-6 partitioning also three levels of partioning are used, in this case 6-by-6, 12-by-12, 24-by-24. And so on.

Question: How to create an alternative ImagePartition function that creates a finer grid closer to the centre of the image. The output lists should be arranged in such a way that it is easy to re-assemble the image from the pieces.

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2 Answers 2

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You can iterate ImagePartiton on different sub-levels of previously applied ImagePartiton. 

i = ExampleData[{"TestImage", "Lena"}]
p1 = ImagePartition[i, {100, 100}]; p1 // GraphicsGrid

enter image description here

Now pick the middle of your list and replace its elements with finer partiton:

p2 = p1; p2[[2 ;; -2, 2 ;; -2]] = Map[GraphicsGrid[ImagePartition[#, {20, 20}], 
Spacings -> 0, Frame -> All, FrameStyle -> White, ImageSize -> 100] &, 
p1[[2 ;; -2, 2 ;; -2]], {2}]; Grid[p2, Spacings -> .3]

enter image description here

You can remove all grid wrappers of course - I kept them for visual comprehension. This is easy to pack into a function. You can continue partitioning in the same manner. Is this what you had in mind?

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  • $\begingroup$ Wow! - Yes, image-wise this is about what I had in mind, but I need the parts for further processing in my program like ImagePartition. I'll study your answer first. $\endgroup$
    – nilo de roock
    Commented Aug 1, 2012 at 10:52
  • $\begingroup$ Could you elaborate a bit on the Spacings Option you used. I am trying to get an equal spacing overall but that doesn't really work. Also setting spacings to 0 doesn't remove the horizontal spacing but it does so with the vertical spacing. $\endgroup$
    – nilo de roock
    Commented Aug 1, 2012 at 11:41
  • $\begingroup$ @ndroock1 Spacings option is for grid only. I thought you will omit Grid, because you need the list structure only. Nested grid structures are not really good things to have. $\endgroup$
    – Vitaliy Kaurov
    Commented Aug 1, 2012 at 15:29
  • $\begingroup$ Yes, I will. I got it now, although somewhat struggling to make the code generic. But I'll get there. I always do. $\endgroup$
    – nilo de roock
    Commented Aug 1, 2012 at 18:10
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It seems quad-tree decomposition would suit your needs: enter image description here http://demonstrations.wolfram.com/QuadTreeImageDecomposition/

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  • $\begingroup$ That looks great! Would you please include executable code here, and a description of how to use it? $\endgroup$
    – Mr.Wizard
    Commented Aug 3, 2012 at 17:10
  • $\begingroup$ @Mr.Wizard - Good answer, I agree, although not useful in my app. But you ask the OP to copy code from the Wolfram Demos site. Isn't the link sufficient? $\endgroup$
    – nilo de roock
    Commented Aug 7, 2012 at 9:31
  • $\begingroup$ @ndroock1 generally links alone are not considered good StackExchange answers, but I don't have time to find references for that statement right now. $\endgroup$
    – Mr.Wizard
    Commented Aug 7, 2012 at 9:37
  • $\begingroup$ I'll take your word for it @Mr.Wizard $\endgroup$
    – nilo de roock
    Commented Aug 7, 2012 at 10:12
  • $\begingroup$ @Mr.Wizard I'll have to leave that to the interested readers. I just do not have the time right now to look into the potential licensing issues relevant to copying code from the Wolfram Demonstration website. $\endgroup$
    – Matthias Odisio
    Commented Aug 8, 2012 at 15:45

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