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I have an image:

pic = Import[
  "http://note.youdao.com/yws/public/resource/\
2c5a562224240edcf1631fcd39810f56/55FA538207424C0A98AB548724994AE1"]

enter link description here

that I want to binarize. When I try to do it in Mathematica, the results is enter image description here

My code is

bin = MorphologicalBinarize[pic // ColorNegate, {0.4, 0.6}]

I tried this many times. The result was always bad. I want to binarize the image so I can count the lattice (including that adjacent to the border). Can anyone help me?

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  • 1
    $\begingroup$ Can you try reposting your first image to imgur? $\endgroup$ – J. M.'s discontentment Jul 5 '15 at 14:22
  • 3
    $\begingroup$ From the looks of your output image (please repost the original though) you should try LocalAdaptiveBinarize. $\endgroup$ – user484 Jul 5 '15 at 19:51
  • $\begingroup$ @J.M. Can I repost my picture to imgur when I'm commenting? $\endgroup$ – yode Dec 10 '15 at 6:10
  • $\begingroup$ Sure, why not?${}$ $\endgroup$ – J. M.'s discontentment Dec 10 '15 at 6:12
  • $\begingroup$ How to do it?Or where is the tutorial? $\endgroup$ – yode Dec 10 '15 at 6:14
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As suggested by Rahul, LocalAdaptiveBinarize is your friend:

LocalAdaptiveBinarize[pic, 15]

enter image description here

In order to count things, you can use the MorphologicalComponents command. Here we colorize it to get a visualization of how well the morphological processing segments the data:

MorphologicalComponents[LocalAdaptiveBinarize[pic, 15]] // Colorize

enter image description here

Of course, MorphologicalComponents is very versatile and can help gather statistics about your image and the segmentation.

| improve this answer | |
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  • 1
    $\begingroup$ +1, I would also suggest a bigger radius so you don't get the extra noise in the middle of the pieces. $\endgroup$ – user484 Jul 6 '15 at 15:05

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