This question already has an answer here:

I am using ListPlot:

 ListPlot[dpl[[All, 1, {1, 3}]], Frame -> True,
 FrameLabel -> {SubsuperscriptBox["\[Xi]", "in", ""] // DisplayForm,
 "Inefficiency \[CapitalDelta]"}, 
 Joined -> True,
 PlotLabel -> {SubsuperscriptBox["\[Xi]", "out", ""] // DisplayForm} ~~
 ToString[dpl[[1, 2, 2]]]] 

However this gives me a poor y-label: '$\{\xi_{out}\} \~\~ 7$'. How do I get this code to display '$\xi_{out}=7$'?


marked as duplicate by Jens, Bob Hanlon, MarcoB, Oleksandr R., J. M. is away Jun 30 '15 at 3:02

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  • $\begingroup$ I don't understand the question. Please show a self-contained example, explain what you expect and how that differs from what you get. The PlotLabel -> { ... // DisplayForm} ~~ ToString[...] part of the code doesn't seem to make sense, and it's not clear to me what you are trying to achieve with ~~, which is an operator for use with string patterns. $\endgroup$ – Szabolcs Jun 29 '15 at 15:33
  • 1
    $\begingroup$ Maybe you are looking for PlotLabel -> (TraditionalForm@HoldForm[Subscript[\[Xi], out] = #] &)[ 7]. $\endgroup$ – Szabolcs Jun 29 '15 at 15:36
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  • $\begingroup$ As well as Szabolcs does I do not understand the question, but what I understand is that you (a) use the BoxLanguage incorrectly and (b) in the place where it is easier not to use it, but to make use of more simple tools. In particular, instead of {SubsuperscriptBox["\[Xi]", "in", ""] // DisplayForm you may type Esc+x+Esc then Ctrl+- and then in . You will get what you need, no difficulties. Or also PlotLabel->Style["y=7"] where y=Esc+x+Esc then Ctrl+- and then out You did not explain what is dpl, hence I cannot help more. $\endgroup$ – Alexei Boulbitch Jun 29 '15 at 16:18

I think you are working too hard; i.e, using lower-level forms than you need to. Let Mathematica do the heavy lifting.

plt = Range @ 10;
  Frame -> True,
  FrameLabel -> {Subscript["ξ", "in"], "Inefficiency Δ"}, 
  Joined -> True,
  PlotLabel -> Row[{Subscript["ξ", "out"], "  ", plt}]]



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