2
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How can I make

f[n_Integer]=2*n

valid for a list of integers? For example:

f[nlist_Integer] := 2*nlist[[1]]

does not work because because nlist={1,3,2} is not an integer.

Edit: Same question with NumericQ (which does not work as Integer)?

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  • $\begingroup$ Related: (6588) -- also see the many links therein. And performance notes here may be useful: (8650) $\endgroup$
    – Mr.Wizard
    Jun 16, 2015 at 7:11

1 Answer 1

5
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F[listInt:{__Integer}]:=

The semicolon is just another way to name a pattern

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  • 1
    $\begingroup$ By chance, I just found nList_ /; VectorQ[nList, IntegerQ] reading a question. Your suggestion is shorter. $\endgroup$
    – anderstood
    Jun 16, 2015 at 6:08
  • $\begingroup$ How would you make it work with NumericQ̀? $\endgroup$
    – anderstood
    Jun 16, 2015 at 6:10
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    $\begingroup$ F[listInt:{__Integer}]? $\endgroup$ Jun 16, 2015 at 6:11
  • $\begingroup$ @belisarius Absolutely. It does not work with Integers. $\endgroup$
    – anderstood
    Jun 16, 2015 at 6:12
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    $\begingroup$ @anderstood F[b : {__?NumericQ}]? $\endgroup$ Jun 16, 2015 at 6:24

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