I need to plot the partial function:

$T_f(x)=\log 2+\sum_{k=1}^{\infty}\frac{(-1)^{k+1}}{2^kk}(x-2)^k$

for $n=2$,$n=4$ and $n=6$ on the same plot over the interval $[-\frac{1}{2},4]$ and also the maximum difference between $f$ and these partial sums of $T_f$ in the same interval

And i have no idea how to do it...

  • $\begingroup$ So, you have looked at Table[], Sum[], and Plot[]? $\endgroup$ May 19, 2015 at 15:30

1 Answer 1

Log[2] + Sum[(-1)^(k + 1) (x - 2)^k/(k 2^k), {k, 1, Infinity}]


Since Log is complex or unbounded for non-positive argument, the maximum difference is undefined for x <= 0

Log /@ {0, -1/4} // InputForm

{-Infinity, I*Pi - Log[4]}

The maximum difference will be arbitrarily large as x gets arbitrarily close to 0+.


f[x_, n_] := Log[2] + Sum[(-1)^(k + 1) (x - 2)^k/(k 2^k), {k, 1, n}]

f[x, Infinity]


Plot[Evaluate[Table[f[x, n], {n, {2, 4, 6, Infinity}}]], {x, -1/2, 4}, 
  PlotLegends -> {2, 4, 6, Infinity}] // Quiet

enter image description here


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