I've looked through the other posts on rotating a function around the x or y axis and haven't had any luck.
my question is this how do i rotate the area between the functions $f(x)=x^2+1$, and $f(x)=2x^2-2$, whereby $x>0$ and $y>0$ and the region is bounded by the y and x axis.
This is a plot of the area I'm talking about.
Revolving the area around the y-axis is suppose to produce a vase, although I picture something of a shallow bowl.
Any help would be much appreciated. As I'm still quite new to Mathematica, an explanation of any code posted would be helpful.