I have a confusion recently about the visualization of data.the data you can get here.The construction of data is four dimension,like as {x,y,z,color},this is my current solution.

data = ReadList["2.txt", {Real, Real, Real, Real}];
front = data[[All, 1 ;; 3]];
back = data[[All, 4]];
Graphics3D[Point[front, VertexColors -> Hue /@ Rescale[back]]]

the effect like the picture.

enter image description here

it is not my intention.i want get a cube whose color be determined by the fourth element of the list.

I have an another try like this.


enter image description here

the shape is contented to me.But I cannot render it by what I want to.Can anybody help me?

  • $\begingroup$ Something like: 19575? $\endgroup$ – Kuba Apr 25 '15 at 13:48
  • $\begingroup$ @Kuba,yeah,thk your concern this problem.I have read that some times,but there are two difference,first,the first solution's point is not a face.the scene is same to my first picture. the scond solution 's data isn't a coordinates.so i want to get a new method. $\endgroup$ – yode Apr 25 '15 at 14:01
  • $\begingroup$ and all my data is the surface of a cube. $\endgroup$ – yode Apr 26 '15 at 3:47
MeshCells[DelaunayMesh[front], 2], VertexColors -> Hue /@ back]}]

MeshCoordinates[DelaunayMesh[front]] == front


enter image description here

  • $\begingroup$ MeshCoordinates[front][[1]] is equivalent to front. $\endgroup$ – LLlAMnYP Apr 27 '15 at 12:45
  • $\begingroup$ @LLlAMnYP Hi, thanks for pointing out that, that might be a typo here though the same to front, my first try is MeshCoordinates[DelaunayMesh[front]] $\endgroup$ – HyperGroups Apr 27 '15 at 13:14
  • $\begingroup$ Also with some fiddling it seems that VertexColors->Hue/@(Rescale@back)yield a more meaningful picture. $\endgroup$ – LLlAMnYP Apr 27 '15 at 13:27

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